sql server – Will index on a partition that doesn’t include partition column work fast?

Let’s say I have a huge table with columns (CloseOfBusinessDate), (DataSourceID), etc.

(CloseOfBusinessDate) is a partition column and I have a clustered index on that column (on CloseOfBusinessDatePartition).

If I add an index on the (DataSourceID) column on the CloseOfBusinessDatePartition, will the following query work fast:

  CloseOfBusinessDate = @cobDate 
  AND DataSourceID    = @dataSourceID

I.e., I expect SQL Server to quickly find the right partition and then use the index on the DataSourceID column for the fastest results. Am I right?

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twrp – Trying to (fast) boot: Error verifying the received boot.img

As described in this answer by @irfan-latif, I am trying to boot (without flashing) my Google Pixel 3a into TWRP via the following command:

fastboot boot twrp-3.5.2_9-0-sargo.img

This failed with the following messages:

Sending 'boot.img' (65536 KB)                      OKAY (  2.028s)
Booting                                            FAILED (remote: 'Error verifying the received boot.img: Invalid Parameter')
fastboot: error: Command failed

The only things I found on this topic are:

What caused the error, can it be resolved, and if so, how?

P.S. Further details:

$ adb --version
Android Debug Bridge version 1.0.41
Version 31.0.2-7242960
$ fastboot --version
fastboot version 31.0.2-7242960
  • I have unlocked the bootloader.
  • I also tried booting the LineageOS recovery which appears to work, but continues starting Android normally instead of TWRP:
$ fastboot -v boot lineage-18.1-20210608-recovery-sargo.img
Sending 'boot.img' (65536 KB)                      OKAY (  2.004s)
Booting                                            OKAY (  7.085s)
Finished. Total time: 9.156s

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How fast in DnD terms is the word "immediately"?

For example, the spell Sending says:

You send a short message of twenty-five words or less to a creature
with which you are familiar. The creature hears the message in its
mind, recognizes you as the sender if it knows you, and can answer in
a like manner immediately. The spell enables creatures with
Intelligence scores of at least 1 to understand the meaning of your

Does this mean within one round/6 seconds? Or does it mean within the creature’s next action?

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(C#) Sudoku board validation algorithm. It is already fast on my machine and I wonder how I can make it significantly faster, if at all (for fun)

I tested this algorithm on 9×9 boards and on average, if the board passed to the function is a (valid) solution, it takes 0.13-0.14 seconds for 1 million executions on my machine. I ran my code in Release mode in Visual Studio and timed it using Stopwatch. I found the idea to use summing of all digits in rows, columns and square cells from another StackOverflow post on suggestions for making a sudoku validator. Note that I gave my code capabilities to work with perfect squares (perfect square is assumed in code) for the board size, where the size is assumed to be the same in all dimensions. I am also planning to build a sudoku solver in the near future.

The sudoku board validating function:

public static bool IsValidSudokuBoard(int()() board)
    int size = board.Length, cellSize = (int)Math.Sqrt(size), sumOfAllNums = (int)SumAllUpTo(size);
    for (int row = 0; row < size; row++)
        if (Sum(board(row)) != sumOfAllNums)
            return false;
    for (int column = 0; column < size; column++)
        int columnSum = 0;
        for (int row = 0; row < size; row++)
            columnSum += board(row)(column);
        if (columnSum != sumOfAllNums)
            return false;
    for (int row = 0; row < size; row += cellSize)
        for (int column = 0; column < size; column += cellSize)
            int cellSum = 0;
            for (int rowOffset = 0; rowOffset < cellSize; rowOffset++)
                for (int columnOffset = 0; columnOffset < cellSize; columnOffset++)
                    cellSum += board(row + rowOffset)(column + columnOffset);
            if (cellSum != sumOfAllNums)
                return false;
    return true;

Where SumAllUpTo is defined as follows:

public static double SumAllUpTo(double end, double start = 0d)
    => end * Math.Floor((end + 1d) / 2d) - ((start == 0d) ? 0d : SumAllUpTo(start));

And Sum is defined as follows:

public static int Sum(this int() array)
    int result = 0;
    for (int x = 0; x < array.Length; x++)
        result += array(x);
    return result;

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