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CPU 4 x 3.40 GHz
16 GB of DDR3 RAM
500 GB hard drive storage
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CPU 4 x 3.50 GHz
16GB DDR4 ECC RAM
1TB HDD storage
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16GB DDR4 ECC RAM
1TB HDD storage
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formulas – SEARCH for data from another sheet

So I have a drop-down menu in order sheet and I have a info sheet. In the information sheet, I have 2 columns, column A has the customer's name, column second You have the customer's email.

So, what I would like to do is, in the order form, select the name of a client, then the column next to it will automatically complete your email address.

I have 43 clients with 43 emails and it is inconvenient to select the client (IE Joe H.) and try to find the email of other users in another drop-down list. If I could self-populate it would be good.

Basically, I was looking at the `YES` command or `SEARCH FOR` command and I'm a bit confused that best suits my needs.

If column A in order of leaves is `Joe`then column second in order the sheets is automatically `Joe@gmail.com`, if column A is `Jack` then column second is `Jack@yahoo.com` and so.

Data structures – Probability lower limit in the double loop in the cuckoo chart

I read Chater 17. Balanced assignments and
Cuckoo Hashing in Mitzenmacher. Upfal. Probability and computation: randomization and probabilistic techniques in algorithms and data analysis and got stuck with two problems.

We have $$m$$ elements and $$n$$ cubes Each element is divided into two random groups (we assume that two of our hash functions are completely random).
If each cube corresponds to a vertex and each element corresponds to a
edge. So we have a random graph with $$n$$ vertices and $$m$$ borders
The loops and multi-edges are permitted.

1. The first problem is about the probability of reconstructing the entire cuckoo hash table. We rebuild (reinsert all elements with new hash functions) a cuckoo hash table when a connected component
It has a double cycle. We can calculate the probability that after inserting
an element produces a double cycle. This probability is $$mathcal {O} (1 / n ^ 2)$$.
To test this, we consider the situation when the last inserted element creates a double cycle in exactly $$k$$ elements. Then before insertion.
there was $$k$$ edges between these $$k$$ vertices. exist $${n} choose {k}$$
ways to choose these vertices, and $${m} choose {k}$$ Ways to choose the elements that correspond to the edges. Then the authors write the following.
phrase that I do not understand but I think it is something crucial:

After adding the new edge for the inserted element, the edges k + 1 must
form an expansion tree, as well as two additional edges.

Not to do $$k + 1$$ Do edges involve forming a double cycle, not an expansion tree?
Was not the expansion tree formed even before insertion since we had? $$k$$ vertices and $$k$$ edges between them?
Also, I do not understand why two additional edges should form an expansion tree and how does this relate to what we want to test?

Next, the authors write the probability formula that we want to calculate:

$${n} choose {k}$$ $${m} choose {k}$$ $$k ^ {k – 2}$$ $${k + 1} choose {2}$$ $$(k – 1)! cdot points$$.

This formula is not complete, but my question about this part. here $$k ^ {k – 2}$$ – the number of trees in $$k$$ vertices
$$(k-1)!$$ – The number of ways to map. $$k-1$$ elements in $$k-1$$ borders
I do not understand the term $${k + 1} choose {2}$$. Because we chose $$2$$ edges of $$k + 1$$. Should not we choose a single edge of $$k$$ edges My point is that $$k – 1$$ the edges form an expansion tree in $$k$$ The vertices and a remaining edge, as well as the edge corresponding to the new element, must form two cycles. Then we can choose the remaining edge in $$k$$ shapes. I think the formula should be:

$${n} choose {k}$$ $${m} choose {k}$$ $$k ^ {k – 2}$$ $$k$$ $$(k – 1)! cdot points$$.

Could you please explain the details? Could it be that I do not understand something?

2. The second thing I do not understand is about the lower limit of probability
have a double cycle in two vertices (without auto-loops).
To estimate it, the authors first calculate the expected number of double cycles in two vertices.
Is $${m} choose {3}$$ $$(1 – frac {1} {n}) ( frac {2} {n ^ 2}) ^ 2$$.
here $$(1 – frac {1} {n})$$ It is likely that the first edge does not form a self-loop. Y $$( frac {2} {n ^ 2}) ^ 2$$ It is likely that the two remaining edges
they are between the same two vertices as the first.
Then the authors write:

We easily see that when $$m = Omega (n)$$ this expectation is
$$Omega (1 / n)$$. A variance calculation easily produces the
probability that there
It is such a triple is also $$Omega (1 / n)$$, using the second-moment method.

As I understood, the authors mean that using the second-moment method ($$P (X = 0) le frac {Var[X]}{(MY[X]) ^ 2}$$), we can achieve that $$P (X ge 1) = 1 – P (X = 0) ge 1 – frac {Var[X]}{(MY[X]) ^ 2} ge 1 – n ^ 2 Var[X] = Omega (1 / n)$$.
here $$X$$ It is a random variable that is equal to the number of edge triples.
that form double cycle in two vertices.
So this means that Var[X] It should be $$frac {1} {n ^ 2} – Theta ( frac {1} {n ^ 3})$$. I tried to calculate the variance using the formula
$$Var[sum_i X] = sum_i Var[X_i] + sum_ {i not = j} Cov (X_i, X_j)$$ as
$$X_i$$ Y $$X_j$$ they are not independent
here $$X_i$$ is a random variable of indicator that is equal to one when $$i$$-th
The triple of edges forms a double cycle in two vertices.
But I always get a complicated formula that seems $$c_1 cdot frac {1} {n} + c_2 cdot frac {1} {n ^ 2} + c_3 frac {1} {n ^ 3}$$.
here $$c_1 cdot frac {1} {n}$$ appears due to the term $$sum_i Var[X_i]$$ and from $$Var[X_i] = Theta (1 / n ^ 2)$$.
Is there a simpler way to calculate the variance and show that $$P (X ge 1) = Omega (1 / n)$$?

Thank you!

appsec – Can my machine be compromised if I use an outdated application and the input data is reliable?

Suppose I decide to use an obsolete application for some reason: maybe I can not update it for compatibility reasons, or the updates are not provided in the official repositories I use, or maybe I do not feel like updating it because it just works And I see no reason to update it As far as I know, this application could be full of vulnerabilities that were only patched in later versions.

I suppose it is safe to use an obsolete application as long as the entry is trusted and that there is no port to communicate on the Internet, but I am not sure if I am missing something.

File management – Transferring data from the application to another Android device

I have a lot of data written by the ColorNote application. Now I installed the ColorNote on another Android device, too.

Now, how to copy my ColorNote data from the original device to that device (with the new installation of ColorNote)?

I do not know where ColorNote writes the data written by its user 🙁

Site printing versus URL printing: Search Console as a data source in Data Studio

Could someone explain to me what is the difference between `site printing` Y `url printing`, if I connect Search Console as a data source to Data Studio? Look at the screenshot:

I have compared the data fields of both, they seem to be the same … 🙁 At least I could not find a difference.

web application – How do I extract the data from the response and use it in the URL for the next request in Burp Intruder?

URL = https://www.example.com/send?session=abcabcabc

When the previous url is requested, an answer comes with < a > tag that contains a new URL with different session values ​​like: https://www.example.com/send?session=xyzxyzxyz

As you can see, the value of the session has changed and has changed in each request.

So, my question is, how can I use the Burp intruder to make repeated requests?

The workflow must be:

Burp> request sent> get response> take url or response session value> send request with session value updated in url> loop continues.

vba – Find and compare data from two Excel files

I need to compare the time slots in two Excel files after identifying the corresponding user. The files look something like this

Y

The user ID for Name1 Surname1 in the first file is 35.

In the second, the user ID is 56 and is always preceded by #.

After verifying that Name1 Surname1 (1st) is the same as Last1, First1 (2nd), you should be able to create a correspondence table between the user IDs in both tables, that is, 35 <- 56, which will not change.

The user ID in the second is in G76, and the times of IN and OUT for that user are in AR80 and BT80, always with 4 rows down, always with columns AR and BT.

At this point, I need to compare ShiftStartTime and ShiftEndTime in the first with IN and OUT in the second, to establish the differences.

The way I thought about this was to look up Surname1, Name1 # 56 in column G of the second file to find the row, and then quit to compare the times.

Question. It is a macro in Excel VBA capable of doing all this, and someone can give an example of how the code could look.

python – WxPython GUI to display Adafruit IO data

I need to create a GUI using WxPython in the form of a speedometer to show 9 different data values ​​obtained from Adafruit IO. My code is shown below:

``````import wx
import wx.lib.agw.speedmeter as SM
import time
from mathematics import pi
import numpy as np

global ap1
global ap2
global ap3
global lc1
global lc2
global lc3
lv1 global
global lv2
lv3 global

ap1 = 0
ap2 = 0
ap3 = 0
lc1 = 0
lc2 = 0
lc3 = 0
lv1 = 0
lv2 = 0
lv3 = 0

PanelOne class (wx.Panel):
def __init __ (self, parent):
global ap1
global ap2
global ap3
global lc1
global lc2
global lc3
lv1 global
global lv2
lv3 global
wx.Panel .__ init __ (self, parent = parent)
panel = wx.Panel (self, wx.ID_ANY)
panel1 = wx.Panel (panel, wx.ID_ANY, style = wx.SUNKEN_BORDER)

self.speed1 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed2 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed3 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed4 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed5 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed6 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed7 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed8 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)
self.speed9 = SM.SpeedMeter (panel1, -1, agwStyle = SM.SM_DRAW_HAND | SM.SM_DRAW_SECTORS | SM.SM_DRAW_MIDDLE_TEXT | SM.SM_DRAW_SECONDARY_TICKS, size = (200,200)

self.speed1.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed2.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed3.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed4.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed5.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed6.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed7.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed8.SetAngleRange (-pi / 6, 7 * pi / 6)
self.speed9.SetAngleRange (-pi / 6, 7 * pi / 6)

interval1 = [0, 0.00001, 0.00002, 0.00003, 0.00004, 0.00005, 0.00006, 0.00007, 0.00008, 0.00009, 0.0001]
interval2 = [0, 0.01, 0.02, 0.03, 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.1]
interval 3 = [0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1]
interval 4 = [0, 30, 60, 90, 120, 150, 180, 210, 240, 270, 300]
interval5 = [0, 0.0001, 0.0002, 0.0003, 0.0004, 0.0005, 0.0006, 0.0007, 0.0008, 0.0009, 0.001]

self.speed1.SetIntervals (interval1)
self.speed2.SetIntervals (interval1)
self.speed3.SetIntervals (interval2)
self.speed4.SetIntervals (interval1)
self.speed5.SetIntervals (interval5)
self.speed6.SetIntervals (interval3)
self.speed7.SetIntervals (interval4)
self.speed8.SetIntervals (interval4)
self.speed9.SetIntervals (interval4)

color1 = [wx.BLACK]* 10

self.speed1.SetIntervalColours (color1)
self.speed2.SetIntervalColours (color1)
self.speed3.SetIntervalColours (color1)
self.speed4.SetIntervalColours (color1)
self.speed5.SetIntervalColours (color1)
self.speed6.SetIntervalColours (color1)
self.speed7.SetIntervalColours (color1)
self.speed8.SetIntervalColours (color1)
self.speed9.SetIntervalColours (color1)

tick1 = [str(interval) for interval in interval1]
tick2 = [str(interval) for interval in interval2]
tick3 = [str(interval) for interval in interval3]
tick4 = [str(interval) for interval in interval4]
tick5 = [str(interval) for interval in interval5]

self.speed1.SetTicks (tick1)
self.speed1.SetTicksColour (wx.WHITE)
self.speed1.SetNumberOfSecondaryTicks (5)
self.speed1.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed1.SetMiddleText ("Active Power 1")
self.speed1.SetMiddleTextColour (wx.WHITE)
self.speed1.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed1.SetHandColour (wx.Colour (255, 50, 0))
self.speed1.DrawExternalArc (False)
self.speed1.SetSpeedValue (0)

self.speed2.SetTicks (tick1)
self.speed2.SetTicksColour (wx.WHITE)
self.speed2.SetNumberOfSecondaryTicks (5)
self.speed2.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed2.SetMiddleText ("Active Power 2")
self.speed2.SetMiddleTextColour (wx.WHITE)
self.speed2.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed2.SetHandColour (wx.Colour (255, 50, 0))
self.speed2.DrawExternalArc (False)
self.speed2.SetSpeedValue (0)

self.speed3.SetTicks (tick2)
self.speed3.SetTicksColour (wx.WHITE)
self.speed3.SetNumberOfSecondaryTicks (5)
self.speed3.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed3.SetMiddleText ("Active Power 3")
self.speed3.SetMiddleTextColour (wx.WHITE)
self.speed3.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed3.SetHandColour (wx.Colour (255, 50, 0))
self.speed3.DrawExternalArc (False)
self.speed3.SetSpeedValue (0)

self.speed4.SetTicks (tick1)
self.speed4.SetTicksColour (wx.WHITE)
self.speed4.SetNumberOfSecondaryTicks (5)
self.speed4.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed4.SetMiddleText ("Line Current 1")
self.speed4.SetMiddleTextColour (wx.WHITE)
self.speed4.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed4.SetHandColour (wx.Colour (255, 50, 0))
self.speed4.DrawExternalArc (False)
self.speed4.SetSpeedValue (0)

self.speed5.SetTicks (tick5)
self.speed5.SetTicksColour (wx.WHITE)
self.speed5.SetNumberOfSecondaryTicks (5)
self.speed5.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed5.SetMiddleText ("Line Current 2")
self.speed5.SetMiddleTextColour (wx.WHITE)
self.speed5.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed5.SetHandColour (wx.Colour (255, 50, 0))
self.speed5.DrawExternalArc (False)
self.speed5.SetSpeedValue (0)

self.speed6.SetTicks (tick2)
self.speed6.SetTicksColour (wx.WHITE)
self.speed6.SetNumberOfSecondaryTicks (5)
self.speed6.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed6.SetMiddleText ("Line Current 3")
self.speed6.SetMiddleTextColour (wx.WHITE)
self.speed6.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed6.SetHandColour (wx.Colour (255, 50, 0))
self.speed6.DrawExternalArc (False)
self.speed6.SetSpeedValue (0)

self.speed7.SetTicks (tick4)
self.speed7.SetTicksColour (wx.WHITE)
self.speed7.SetNumberOfSecondaryTicks (5)
self.speed7.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed7.SetMiddleText ("Line Voltage 1")
self.speed7.SetMiddleTextColour (wx.WHITE)
self.speed7.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed7.SetHandColour (wx.Colour (255, 50, 0))
self.speed7.DrawExternalArc (False)
self.speed7.SetSpeedValue (0)

self.speed8.SetTicks (tick4)
self.speed8.SetTicksColour (wx.WHITE)
self.speed8.SetNumberOfSecondaryTicks (5)
self.speed8.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed8.SetMiddleText ("Line Voltage 2")
self.speed8.SetMiddleTextColour (wx.WHITE)
self.speed8.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed8.SetHandColour (wx.Colour (255, 50, 0))
self.speed8.DrawExternalArc (False)
self.speed8.SetSpeedValue (0)

self.speed9.SetTicks (tick4)
self.speed9.SetTicksColour (wx.WHITE)
self.speed9.SetNumberOfSecondaryTicks (5)
self.speed9.SetTicksFont (wx.Font (7, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_NORMAL))
self.speed9.SetMiddleText ("Line Voltage 3")
self.speed9.SetMiddleTextColour (wx.WHITE)
self.speed9.SetMiddleTextFont (wx.Font (8, wx.FONTFAMILY_SWISS, wx.FONTSTYLE_NORMAL, wx.FONTWEIGHT_BOLD))
self.speed9.SetHandColour (wx.Colour (255, 50, 0))
self.speed9.DrawExternalArc (False)
self.speed9.SetSpeedValue (0)

vsizer1 = wx.BoxSizer (wx.VERTICAL)
hsizer1 = wx.BoxSizer (wx.HORIZONTAL)
hsizer2 = wx.BoxSizer (wx.HORIZONTAL)
hsizer3 = wx.BoxSizer (wx.HORIZONTAL)

panel1.SetSizer (vsizer1)
panel1.Fit ()
mainSizer = wx.BoxSizer (wx.VERTICAL)
self.SetSizer (mainSizer)
mainSizer.Layout ()

self.timer = wx.Timer (self)
self.Bind (wx.EVT_TIMER, self.on_timer, self.timer)
self.timer.Start (1)
Self.Show (True)

def on_timer (auto, event):
global ap1
global ap2
global ap3
global lc1
global lc2
global lc3
lv1 global
global lv2
lv3 global

ap1 = float ((aio.receive (& # 39; activepower-kt1 & # 39;)) value.
ap2 = float ((aio.receive (& # 39; activepower-kt2 & # 39;)) value.
ap3 = float ((aio.receive (& # 39; activepower-kt3 & # 39;)) value.
lc1 = float ((aio.receive (& # 39; linecurrent-i1 & # 39;)) value.
lc2 = float ((aio.receive (& # 39; linecurrent-i2 & # 39;)). value)
lc3 = float ((aio.receive (& # 39; linecurrent-i3 & # 39;)) value.
lv1 = float ((aio.receive (& # 39; linevoltage-v1 & # 39;)). value)
lv2 = float ((aio.receive (& # 39; linevoltage-v2 & # 39;)) value.
lv3 = float ((aio.receive (& # 39; linevoltage-v3 & # 39;). value)

self.speed1.SetSpeedValue (ap1)
self.speed2.SetSpeedValue (ap2)
self.speed3.SetSpeedValue (ap3)
self.speed4.SetSpeedValue (lc1)
self.speed5.SetSpeedValue (lc2)
self.speed6.SetSpeedValue (lc3)
self.speed7.SetSpeedValue (lv1)
self.speed8.SetSpeedValue (lv2)
self.speed9.SetSpeedValue (lv3)

MyApp class (wx.App):
Def OnInit (auto):
title = "GUI of the energy meter"
pos = (200,200)
size = (570,280)
self.frame = class_myframe (title, pos, size)
self.frame.Show (True)
self.SetTopWindow (self.frame)
return true

class class_myframe (wx.Frame):
def __init __ (auto, title, pos, size):
wx.Frame .__ init __ (auto, None, wx.ID_ANY, title, pos, size)
self.panel_one = PanelOne (self)
self.boxsizer = wx.BoxSizer (wx.VERTICAL)
self.SetSizer (self.boxsizer)
self.boxsizer.Fit (self)
self.boxsizer.Layout ()

app = MyApp (False)
app.MainLoop ()
``````

This code does what it is supposed to do very well. However, it hangs up quite frequently and then updates the values ​​after a while. Is there any way to optimize it more?

schema.org – Reviews of structured data in the knowledge panel

I need help for my site to appear in the knowledge panel as a source of review for the companies that we have listed in our directory. The reviews of our suppliers appear in the search fragments, but not in the knowledge panel when our competitors with much fewer evaluations are. We have worked on the best practices to improve our marking, but we would love to have a second opinion to see if there is something we are missing.

We have all our channels working well (PPC, social, organic, etc.).

I am focusing on getting this problem from having us as a source of review by working on the knowledge panel since our smaller competitors are there, but we are not doing it.

For example, take this place on our website: https://evntsrc.ca/2DcUGUK

You have 145 of our own comments.

We are the first result and it shows our star rating, opinions and price range. However, we do not appear in the knowledge panel, this happens in almost every business that we have listed on our site.

In this particular example, the knowledge panel has in Ville Catering with 45 evaluations.

I can not find any error in our structured data, but I see it in our competition.

[Apologies, I had to remove links to our competitors and the links to their Structured Data Testing tool to get below the 8 link limit.]

Example 2:

Our website: https://evntsrc.ca/2ARosgj

Structured data test tool: https://evntsrc.ca/2FsAJMh

Example 3: