## javascript – Get input values ​​and insert in Onclick

I have a form and I need that when clicking on the button, send parameters of what has been written in the input fields within the url function of the onclick:

``````

``````

Can you help me?

Thank you!

## partitions – partition values ​​in a sequence

I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a sequence list, one for each line that is visible when the sequence is plotted?

Here is the beginning of the sequence:

``````List = {2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163 , 59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583 1601,401,557,337,853,1733,349,883,197};
``````

Thank you.

cheers,
Jamie

## views – How can I get field definition values ​​in a hook_views_query_alter?

This is a bit related to my previous question, I'm using a hook_views_query_alter to show only the results of the last (last) value in a list field, and then in that set only results with the last (last) value are shown in another list field. So, with a lot of articles, I want to show the ones from the last edition in the last volume. I think I'll need these field values ​​to use in my query, but I'm lost trying to get them, for example, in `\$ ver-> field["field_article_volume"]`. Now I'm wondering if I'm doing this correctly, this seems to be a common scenario, so I'd hate to make it more complicated than it should be. Is there a way to take those field values ​​and use them as arguments in the functions of my assistant and then alter the condition value?

## placeholder – Material UI Multiple selection of different code value and visible value – show keys instead of values

I am using Material UI Multiple Select based on the documentation example. I need to save the identification of the selected option and show the name, so I render the object. When I used the documentation example with the placeholder, I see identifiers instead of selected names.
See: https://codesandbox.io/s/kxz5yqmrzv?from-embed

``````names const = [
{ id: "a", name: "Oliver Hansen" },
{ id: "b", name: "Van Henry" },
{ id: "c", name: "April Tucker" },
{ id: "d", name: "Ralph Hubbard" },
{ id: "e", name: "Omar Alexander" },
{ id: "f", name: "Carlos Abbott" },
{ id: "g", name: "Miriam Wagner" },
{ id: "h", name: "Bradley Wilkerson" },
{ id: "i", name: "Virginia Andrews" },
{ id: "j", name: "Kelly Snyder" }
];

<Select
multiple
displayEmpty
value = {this.state.name}
onChange = {this.handleChange}
entry = {}
renderValue = {selected => {
if (selected.length === 0) {
he came back Position marker;
}

return selected.join (",");
}}
>

Position marker

{nombre.map (name => (

{name}

))}

``````

## mysql – Query is not updating null values

I'm analyzing data from a student bank, the data is entered by the users themselves, and I can not change the format of the tables and the bank itself, just modify the values ​​of the records to standardize some fields.

In the nationality field, there are some wrong Brazilian records, written as a bracelet or Brazilian, etc. The registries of other nationalities did not want to modify, so I made the following query, that list in the query are all the other registries outside the Brazilians:

``````UPDATE base
In the case of women,
(In the case of women, in the case of women).
``````

In the field I still had some null values. In the case that it is not in the operating system, My question is precisely why it was not updated?

## Same row twice in \$ view-> result with different values

I need to have different values ​​in each row according to the same row, so I create \$ this_row from \$ row. But field_x contains the same value in the rendered view. I suppose that the reference of \$ row is the same and I tried to clone \$ row without success and also deep_copy but it exceeded the memory.

What else can I try? Any ideas?

``````# in ..._ views_pre_render

\$ new_rows = array ();
foreach (\$ view-> result as \$ row) {
foreach (\$ xs as \$ x) {
\$ this_row = \$ row;
\$ this_field = \$ this_row -> _ entity-> get (& # 39; field_x & # 39;);
\$ this_field-> setValue (\$ x);
\$ new_rows[] = \$ this_row;
}
}
\$ view-> result = \$ new_rows;
``````

## Chain manipulation – Text with dynamic values.

Data set:

``````X = data set[{[{[{[{<|"userId" -> 5315, "Assignment 3" -> 0.71875`,
"A3Grades" -> 71.875`, "ColorCode" -> "Yellow",
"totalpointsA3" -> 46, "Passingpoints" -> 38.4`,
"AveragePoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 1.2857142857142847` |> <|"userId" -> 5326,
"Assignment 3" -> 0.90625`, "A3Grades" -> 90.625`,
"ColorCode" -> "Green", "totalpointsA3" -> 58,
"Waypoints" -> 38.4`, "Midpoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 0.` |>, <|"userId" -> 5327,
"Assignment 3" -> 0.71875`, "A3Grades" -> 71.875`,
"ColorCode" -> "Yellow", "totalpointsA3" -> 46,
"Waypoints" -> 38.4`, "Midpoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 1.2857142857142847` |> <|"userId" -> 5328,
"Assignment3" -> 1.`, "A3Grades" -> 100 `," ColorCode "->" Green ",
"totalpointsA3" -> 64, "Passingpoints" -> 38.4`,
"AveragePoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 0.` |>, <|"userId" -> 5329,
"Assignment 3" -> 0.6875`, "A3Grades" -> 68.75`,
"ColorCode" -> "Yellow", "totalpointsA3" -> 44,
"Waypoints" -> 38.4`, "Midpoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 3.2857142857142847` |> <|"userId" -> 5330,
"Assignment 3" -> 0.71875`, "A3Grades" -> 71.875`,
"ColorCode" -> "Yellow", "totalpointsA3" -> 46,
"Waypoints" -> 38.4`, "Midpoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 1.2857142857142847` |> <|"userId" -> 5331,
"Assignment3" -> 0.625`, "A3Grades" -> 62.5`,
"ColorCode" -> "Yellow", "totalpointsA3" -> 40,
"Waypoints" -> 38.4`, "Midpoints" -> 47.285714285714285`,
"Pointsreqdforpassing" -> 0.`,
"pointsforabvavg" -> 7.285714285714285` |>}]
``````

I want to attach another column that is called MT, which provides a summary of my performance in text format, along with dynamic performance values.

For example, Congratulations, approved the task with a total performance of Sixty-five%. This time you were below average. With only 4 More points, you could have been above average. It's not too late. I hope to see you among the best next time!

where, the numbers in bold must change dynamically, according to the values ​​A3Grades and pointsforabvavg respectively in the data set.

I have no idea how to change the text dynamically. I tried `Dynamic[values]`, but that did not work in quotes.

## linear algebra – How do the values ​​of \$ a \$ affect the definition of this matrix \$ textbf {A} \$?

Leave
$$textbf {A} = begin {bmatrix} -2 & 0 & 1 \ 0 & -2 & a \ 1 & a & -2 end {bmatrix}$$

Since one of its eigenvalues ​​is equal to $$-2$$, How does your definition vary with $$a$$?

Due to the fact that there is a negative eigenvalue, I know that $$textbf {A}$$ can not be positive (semi-) defined and, from its upper left, minor major
$$| textbf {A} _1 | = -2<0, |textbf{A}_2| = 4 >0$$
I hope to find out what your definition depends on. $$a$$ for the solution to this equation
$$| textbf {A} | = 2a ^ 2-4 = 0 iff a = pm sqrt {2}$$
which would imply that $$textbf {A}$$ is defined negative or semi-definite or indefinite negative if $$a in]- sqrt {2}, sqrt {2}$$

\$[\$[\$ or $$a = pm sqrt {2}$$ or $$a notin [-sqrt{2}, sqrt{2} ]$$ respectively.

However, this is not the answer I received, which is similar to mine, but with $$pm sqrt {3}$$ instead. Why is my reasoning wrong and how do we arrive at the correct answer?

## Move and add to obtain multiplication values?

multiplying by 33 -> $$2 ^ 5 + 2 ^ 0$$
is the same as (num << 5) + 1

and for 65599 as (num << 16) + (num << 6) – (num << 0)

How do you get these numbers, that is, 16.6? I know you can use the registry but is there any other faster way to do this?

## operating systems – Input of values ​​to register files

I'm trying to understand how to register files. The next question is from a previous examination:

The following diagram shows the log file of a simple 8 bits
machine

I do not get the registration files completely but it's R3= AA because it is the third row above?
Then, you enter hexadecimal 0x55 Does DA then write it to AA, which is R3?