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Tag: upper
Character creation: is there an upper limit to the number of advantages you can have?
In Anima: Beyond Fantasy, in the generation of characters, through the use of Disadvantages (up to the limit of three Disadvantages), you can finish with nine Creation Points with which to buy Advantages, many of which cost a Creation Point.
The sheet given by the developers has five spaces for Advantages.
Is this a real cap that I've lost, or just one of the many design flaws?
Integration: Riemann Sum, Upper Lower Riemann Sum and Upper Lower Darboux Sum
Notation:
Sum of Riemann $ {S_ {p}} (f) $
Sum of Riemann upper / lower $ overline {S_ {p}} (f) $/$ underline {S_ {p}} (f) $
Upper / Lower Sum Darboux $ U_p (f) $/$ L_p (f) $
Definition:
Leave $ f:[a,b] rightarrow mathbb {R} $ and to be part of [a,b]
Sum of Riemann:
$$ {S_ {p}} (f) = sum _ {i = 1} ^ n 🙁 x_ix_ {i1}) f (t_i) text {where} t_i in[x_{i1},x_i]$$
Sum of upper / lower Riemann:
$$ overline {S_ {p}} (f) / underline {S_ {p}} (f) = sup {{S_ {p}} (f) } / inf {{S_ {p }} (f) } $$
Sum Darboux upper / lower:
$$ U_p (f) / L_p (f) = sum_ {i = 1} ^ n 🙁 x_ix_ {i1}) sup limits _ {x in[x_{i1},x_i]} f (x) / sum _ {i = 1} ^ n 🙁 x_ix_ {i1}) inf limits _ {x in[x_{i1},x_i]} f (x) $$
Questions:
 In my textbook (perhaps most of the textbook), I only defined the sum of Riemann and the upper / lower Darboux. And I also see that some text uses the upper / lower Darboux sum to define the upper / lower Riemann sum, are they equivalent definitions?
In other words:
$$ sup {{S_ {p}} (f) } / inf {{S_ {p}} (f) } overset? = sum_ {i = 1} ^ n 🙁 x_ix_ {i1}) sup limits _ {x in[x_{i1},x_i]} f (x) / sum _ {i = 1} ^ n 🙁 x_ix_ {i1}) inf limits _ {x in[x_{i1},x_i]} f (x) $$

The upper / lower Riemann sum may or may not be a Riemann sum, since it is taking Infimum and supreme of the whole Riemann sum with the partition p, is there any condition in fop, if it is true, then the sum of Riemann top / bottom must be a Riemann sum?

Also, is there any condition in f or p, if true, then the sum of Riemann's top / bottom must not be a Riemann sum?
Any help would be appreciated.
Why should not the navigation utility be in the upper left?
people
I wonder if any of you know of a source to explain why the navigation utility should not be in the upper left of a web design. I have always considered that the top left on the logo is a blind spot, but I can not find a source to prove it.
Thanks for any help!
ars magica 5 – What is the reasonable upper limit of extraction for an established magician?
When using the basic rule book, Covenants and The Mysteries, what is the reasonable upper limit of the seasonal extraction of a hermetic alchemist that is 75 years old?
The considerations that seem to be synergistic are:
 Specialization in the laboratory: vis extraction.
 Hermetic alchemy greater virtue.
 Bonus of the Verditus house to the total of the alchemy laboratory.
dnd 5e – Is there an upper limit on the number of cards a character can draw from Deck of Many Things?
The cover of many things (DMG, pp. 162164) says:
Before drawing a letter, You must declare how many cards you want to draw. and then draw them at random […] Any letter extracted in excess of this number has no effect. Otherwise, as soon as you draw a card from the deck, its magic will take effect. You must steal each card no more than 1 hour after the previous draw. If you can not draw the chosen number, the remaining number of cards will fly only from the deck and will take effect once.
But it does not seem to specify an upper limit of how many cards can be collected. There is one Because of how dangerous Deck of Many Things can be, I have only seen people pick up to 3, but could you declare 10? 30? fifty?
Geometry: For any surface bounded by a sphere, is there always an upper limit of the set of all the lengths of all the geodesics of shortest length between pairs of points?
Take a surface S. Suppose there is a sphere with a finite radius such that each point on S falls into the sphere. Then, given two points P1 and P2, so that there is a geodesic in S between them, is there an upper limit on the length of the shortest geodesic between these points? Does this upper limit apply to all points on the surface?
I am dealing with an algorithm to find geodesics in certain surfaces and it crumbles if there are two points such that there is only one geodesic and the length is infinite. I know that with the toroidal forms an infinite geodesic can be produced that never repeats itself. However, this path is not the only way to reach certain points and there is an upper limit on the length of all the geodesics of less distance in that way. My concern is where those "infinite" geodesics are the only option.
For the context I am working with surfaces made of triangles only. However my curiosity demands the most general case not strictly polygonal.
Why in any installation indicator (Y / n) the & # 39; Y & # 39; is in upper case and the & # 39; n & # 39; lowercase?
The question itself is selfexplanatory. As another question, I would like to know if it is possible to replace the option & # 39; Y & # 39; with the & # 39; Enter & # 39;
Find an asymptotic upper bound using a recursion tree
The problem is this: use the recursion tree method to get a good asymptotic upper bound on T (n) = 9T (n ^ (1/3)) + BigTheta (1). I can start the tree and find a pattern with the subproblems, but I have a hard time finding the total cost of the execution times in the whole tree. I can not figure out how to get the number of subproblems in depth i when n = 1. I have the feeling that the answer is O (log3 (n)), but I can not verify it at this time. Any help would be appreciated.
T (n) = 9T (n ^ (1/3)) + BigTheta (1) can be written as: T (n) = 9T (n ^ (1/3)) + C, where C is a constant since any constant will always be treated as 1 asymptotically. My recursion tree is explained by each level below: Level 0: this is the constant C
Level 1: T (n ^ (1/3)) is written 9 times, which represents the subproblems of C. This is added to 9cn ^ (1/3).
Level 2: each of the 9 subproblems of level 1 is divided into 9 more subproblems, which are written as T (n ^ (1/9)). All these add up to 81cn ^ (1/9).
Sizes and nodes of the subproblem: the number of nodes in depth i is 9 ^ i We know that the size of the subproblem for a node in depth i is n ^ (1 / (3 ^ i)). The size of the problem reaches n = 1 when this size is equal to 1. Solving for i you get:
(n ^ (1 / (3 ^ i))) ^ (3i) = 1 ^ (3i) n = 1 ^ (3i). This results in n being 1, which does not give a logarithmic form!
Upper limit of the duration of the cycles without chords in dregular graphics
Given a $ d $regular graphic with $ n $ the vertices there is a known upper limit (not trivial) in the duration of the cycles without string in it (presumably depending on $ d $ Y $ n $)? I could not find anything after some online searches. Thank you.