MS Word: When transforming a photo, what causes the photo to have white transformation points versus gray transformation points?

For the photos shown, the same camera was used, but some transformation points (see photos) are white, while other photos have gray points. What causes the difference? What does the difference mean?

White transformation points allow users to select from prefabricated Correction options, where gray transformation points only allow users to change brightness directly

White transformation points

image

Gray transformation points

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Transforming an immutable binary tree without recursion

I am fighting for this. I have a Binary Decision Diagram, which is quite similar to a tree. Each node has a hi node and it. I need to resort to the tree, and if some conditions are the case, replace the node with a new node. The nodes are immutable. So, when I find something that I have to change, I have to return the new version of the node completely. Ultimately, the root changes. Specifically I am trying to implement the RESTRICT algorithm for ROBDD.

And I have! This works fine (C #, sorry?)

        Node Restrict(Node node, Func npoint)
        {
            if (node == context.Term0 || node == context.Term1)
                return node;

            // value has been restricted, replace with true or false path
            if (npoint(node.Variable) is bool value)
                return Restrict(value ? node.Hi : node.Lo, npoint);

            var lo = Restrict(node.Lo, npoint);
            var hi = Restrict(node.Hi, npoint);
            return new Node(node.Variable, lo, hi);
        }

However, my diagram is quite large. And I'm running out of pile space.

So, I am trying to find a way to do this without recurrence. I have tried some things but I have not found anything that works. When I begin to expand it, it becomes quite complicated and I begin to lose track of things.

Can anyone point me any recourse on this?

How smart contracts are transforming the e-commerce industry? – Corner of cryptocurrencies.

TThe blockchain technology has managed to attract the attention of the general public for a while. Although it was the popularity of bitcoins that essentially put blockchain on the roadmap to familiarity, blockchain technology has begun to revolutionize the way the e-commerce industry operates with the introduction of smart contracts.

The application of blockchain technology is best seen in the way smart contracts are designed. Smart contracts are basically agreements that are executed automatically when all the parties involved comply with the required terms and conditions. These agreements are stored in data blocks protected by cryptographic encryption.

Smart contracts have proven to be extremely important for e-commerce operations. When a user makes a purchase through an e-commerce platform, the smart contract is programmed to release the value of the purchase in the seller's wallet only after both the buyer and the seller have met the conditions required to comply with the transaction process. Until then, the amount is retained by the intelligent contract.

Another way in which an intelligent contract operates is by eliminating the intermediaries in the process of the transaction. By doing so, a large amount of money that is usually dedicated to transaction fees is reduced. The ease of making a transaction and the process faster are other side effects of transaction automation with the help of smart contracts.

Searching development of smart contracts Companies? Visit the Blockchain applications factory to obtain high-quality development services from smart contracts.

post processing: the Gimp perspective tool is not really transforming

I have uploaded a screenshot below to illustrate the problem. I dragged a jpeg to Gimp, clicked on the perspective tool and then tried to use it … but as you can see, it's not really transforming the image. Why is this so?

Click to enlarge the image.

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Transforming ParametricFunction into expression depending on the parameter

As a result of resolving an ODE system using ParametricNDSolveValue I get 4 functions, each one of them. Parametric Function depending on the parameter specified in ParametricNDSolveValue.

Even though what I want seems "simple" to me, I have searched the documentation and this site without success, so here is my question:

Can I transform my solution? Parametric Function in an expression of some kind? The motivation is to manipulate this expression, and this may involve different software.

If that is not possible, is there any other way in Mathematics to solve a $ 2 times 2 $ System of EDOs at a point with a free parameter? Here is the question where I first asked about that.

opengl – Transforming a length into a trunk projection

How do I calculate the screen lengths of the position vectors aligned with the axis after a frustum projection transformation?

Background:

In Java I create a frustum projection matrix via

Matrix.frustumM (projMatrix, 0, left, right, top bottom, near, far);

and a view matrix via

Matrix.setLookAtM (viewMatrix, 0,
0, 0, -2.5, // eye position
0, 0, 0 // search position
0, -1, 0); // address above

I also know how many GL units of width and height is the screen of my device, let's say width Y height. If my game tokens are dx Y dy GL units in size, then for a spelling projection I can calculate width / dx Y height / dy to determine how many squares you should have horizontally and vertically (approximately).

But with a trunk projection, which basically is always looking down according to the previous definition, this does not give me the correct result.

(Keep in mind that my tiles are always placed in the x / y airplane in z = -1

Of course I understand why, this is because the further away from the camera the smaller lengths are made. But how do I transform my dx Y dy values ​​to deal with this?

I have tried:

  • divide my dx Y dy by 1 + 2.5 + 1 = 4.5 since that is the distance from the eye to the plane of the tile.

  • Multiplying the projection and view matrices (and both together) by the vector (dx, 0, 0, 1) for example.

But these do not work.

I also hear that the projection matrix has a w component in the lower right part of the matrix, which may have something to do with the z-scale, but I'm not sure if it's on the right track.

Any advice welcome. I will continue investigating.

– primaverabss – Transforming a FP into FA (Sales Documents)

Goodnight everyone,

I am trying to make the transformation of Sales Documents, in the case of a Pro-form in an Invoice, but it gives an error because the origin does not have Warehouse in the Lines.
How can I do to add the store I want?

I have the following code that works if you have Warehouse:


        
        
        
        On Error GoTo Error
Dim objDocOrigen The GcpBEDocumentoVenda
ObjDocOrigen = motor.Comercial.Vendientes.Edita ("000", cbOrigTipoDoc.Text, cbOrigSerie.Text, CInt (cbOrigDoc.Text))

Dim objDocDestino The GcpBedocumentoVenda
objDocDestino = New GcpBEDocumentoVenda
objDocDestino.TipoEntidad = objDocOrigen.TipoEntidad
objDocDestino.Entity = objDocOrigen.Entity
objDocDestino.Tipodoc = cbDestTipoDoc.Text
objDocDestino.Serie = cbDestSerie.Text
objDocDestino.CondPag = objDocOrigem.CondPag

Dim Doc (0) As Object
Doc (0) = objDocOrigen

engine.Commercial.Vendencias.TransformaDocumentoEX (Doc, objDocDestino, True)
GoTo End
of mistake:
MsgBox (Err.Number & ":" & Err.Description)

final:
objDocOrigem = Nothing
objDocDestino = Nothing
LimpaTransShopping ()
cbOrigTipoDoc.Focus ()