React formik after submit form get api want refresh and show

I am react Formik and some also . I want refresh get Api only after create form submit and if user delete also and get Api only refresh’s there any Please help us I stuck
Thank for help

codesandox :https://lbz3x.csb.app/

we will submit 7 days drip feed with 20000 hQ quality social signals With HQ Backlink for $20

we will submit 7 days drip feed with 20000 hQ quality social signals With HQ Backlink

Welcome

I will give 7 Days High Quality Drip Feed SEO Backlinks building service manually

I am a SEO Expert & I am Professional for 7 days Drip Feed SEO Link building Service. I will submit High Quality Backlinks 7 days with daily update. I ensure i will submit hq pr9 and pr10 social signals from best 3 social signals Sites. 100% Effective, Safest, Unique that will Guaranteed your website IMPROVE YOUR GOOGLE RANKINGS.

Drip Feed Service is now becoming very powerful and popular in ranking your website in google first page.

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.(tagsToTranslate)seo(t)smm(t)signal(t)linkbuilding(t)backlink(t)dripfeed

2013 – Submit EditForm event handler with CSR/Jslink


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I do 30 Design infographic and manually submit on High DA/image submission sites for $3

I do 30 Design infographic and manually submit on High DA/image submission sites

I do 30 Design infographic and manually submit on High DA/image submission sites

Discerption

Submittinginfographics or images is one of the most powerful tools for creating quality

backlinks to any website promotion in search engine results,

Design infographics are essential to promote your local business on google to get more traffic. Design infographic is a very powerful and popular tool for online promotion and Google Search Engine Ranking on your website.

Where I will submit your infographic

  • Flickr
  • Twitter
  • Linkedin
  • Pinterest
  • Instagram
  • Imgur
  • visual.ly
  • Photobucket
  • Tumble
  • Facebook
  • SlideShare
  • Etc and more

I will provide you

· All Unique domain blog site

· Web 2.0 HostedDomains

· Totally unique articles

· DA 70 to 90+

· PermanentLive Link

· 100% manually created

· Search Engine Friendly

· Unique IP addresses

· Use white hat SEO Way

· Money-BackGuarantee

· do-follow backlink

· Real Traffic increase quickly more

· Report Submit ByExcel

· Unlimited Revisionsall time

· Must be on time delivery

Requirement

· Address( Street address, City, State, Zip) (Required)

· Phone(Required)

· Website(Required)

· BusinessDescription (Required)

· businessCategory

· business email

· business hours

· Company/Business logo and other images

.(tagsToTranslate)Backlink(t)Image(t)Off(t)page(t)Traffic(t)SEO(t)localseo

mining pools – Stratum: How many shares should I submit per job?

I’m implementing a bitcoin CPU miner just for fun in python. I’ve been reading a lot about bitcoin and the protocol pools use for communication and coordinating workers but there is a key concept I haven’t explicitly found.

The problem (Stratum v1)

Jobs keep coming to the worker(which I store in a FIFO), and provided clean_jobs is set to false, when should I get to the next job? With nonce, extranonce, and version and time rolling seems like I would never need to change job(even with the fastest of ASICs). Or is it that once I found a share for a given job I must submit that only one share and proceed to the next job?

Once a share is found for a given job, should I keep mining it? Until when? Or should I submit that only one share for that job and proceed to the next job?

I’m guessing it is the latter, as the server can adjust the difficulty to prevent me from finding shares too fast(or too slow)

I would appreciate it if you added a source if possible(so I can learn more and see what else I’ve missed).

Error trying to submit webform programatically multiple times: Duplicate entry for key ‘PRIMARY’

I’m trying to programatically send submissions to a webform n times, but when I submit the submission info to the webform for the second time, I get an Integrity constraint violation: 1062 Duplicate entry ‘nnnnn’ for key ‘PRIMARY’ error. It appears the second submission has the same sid as the first submission, but I’m not sure why as I’m submitting NULL for the sid. How can I submit the webform again with the same information, but get a new sid? Drupal 7.

Here is the error in full:

PDOException: SQLSTATE(23000): Integrity constraint violation: 1062 Duplicate entry ‘211-82916-1-0’ for key ‘PRIMARY’: INSERT INTO {webform_submitted_data} (nid, sid, cid, no, data) VALUES (:db_insert_placeholder_0, :db_insert_placeholder_1, :db_insert_placeholder_2, :db_insert_placeholder_3, :db_insert_placeholder_4); Array ( (:db_insert_placeholder_0) => 211 (:db_insert_placeholder_1) => 82916 (:db_insert_placeholder_2) => 1 (:db_insert_placeholder_3) => 0 (:db_insert_placeholder_4) => Bob ) in drupal_write_record() (line 7471 of /var/www/html/includes/common.inc).

And the code:

function wildsight_raffle_tickets_webform_submission_insert($node, $submission) {
  if ($submission->nid == 210) {
     
  $node_out = node_load('211');
  global $user;

  $data = array(
    'first_name' => $submission->data(3)(0),
    'last_name' => $submission->data(4)(0),
    'email' => $submission->data(14)(0),
  );

  module_load_include('inc', 'webform', 'webform.module');
  module_load_include('inc', 'webform', 'includes/webform.submissions');
  
  // This methods will arrange $data in the right way
  $data = _webform_client_form_submit_flatten($node_out, $data);
  $data = webform_submission_data($node_out, $data);

  $submission_out = (object) array(
    'nid' => '211',
    'uid' => $user->uid,
    'sid' => NULL,
    'submitted' => REQUEST_TIME,
    'completed' => REQUEST_TIME,
    'remote_addr' => ip_address(),
    'is_draft' => FALSE,
    'data' => $data,
  );
  
  $number_of_tickets = $submission->data(24)(0);
  while ($number_of_tickets > 0) {
    webform_submission_insert($node_out, $submission_out);
    $number_of_tickets -= 1;
  }
}
}

checkout – Magento2 / Add check for disable submit button on custom payment method

I have developed a payment method for Magento 2. I would like the “send order” button (“invia ordine”) to be disabled in checkout (or send an error message) if the customer does not select an item in the options menu of my method (“seleziona”).

enter image description here

/app/code/Infocurci/Pagamentodilazionato/view/frontend/web/template/payment/pagamentodilazionato.html

<div class="payment-method" data-bind="css: {'_active': (getCode() == isChecked())}">
<div class="payment-method-title field choice">
    <input type="radio"
           name="payment(method)"
           class="radio"
           data-bind="attr: {'id': getCode()}, value: getCode(), checked: isChecked, click: selectPaymentMethod, visible: isRadioButtonVisible()"/>
   <label data-bind="attr: {'for': getCode()}" class="label"><span data-bind="text: getTitle()"></span></label>
                
</div>
<div class="payment-method-content">
    <div>
         
    <select name="payment(condizionipagamento)" class="select input-text required-entry" 
                            data-bind="
                                attr: {id: getCode()+'_condizionipagamento'},
                                options: getCardList(),
                                optionsValue: 'value',
                                optionsText: 'type',
                                optionsCaption: $t('--Please Select--'),
                                ">
                </select>
    </div>
     <!-- ko foreach: getRegion('messages') -->
    <!-- ko template: getTemplate() --><!-- /ko -->
    <!--/ko-->
    <div class="payment-method-billing-address">
        <!-- ko foreach: $parent.getRegion(getBillingAddressFormName()) -->
        <!-- ko template: getTemplate() --><!-- /ko -->
        <!--/ko-->
    </div>
    <div class="checkout-agreements-block">
        <!-- ko foreach: $parent.getRegion('before-place-order') -->
        <!-- ko template: getTemplate() --><!-- /ko -->
        <!--/ko-->
    </div>
    <div class="actions-toolbar">
        <div class="primary">
            <button class="action primary checkout"
                    type="submit"
                    data-bind="
                    click: placeOrder,
                    attr: {title: $t('Place Order')},
                    css: {disabled: !isPlaceOrderActionAllowed()},
                    enable: (getCode() == isChecked())
                    "
                    disabled>
                <span data-bind="i18n: 'Place Order'"></span>
            </button>
        </div>
    </div>
</div>

I Will submit Image or Infographic top 70 high quality PR Websites for $10

I Will submit Image or Infographic top 70 high quality PR Websites

Image or Infographic submission service


Infographic submission is a powerful way to rank your images & websites fast google ranking . Infographic Submission is one of the powerful tool in promoting any website, creating quality backlinks and get referral traffic to your site.

Benefits of Image Infographic Submission :

Your Benefits:

☛ Generating High-quality backlinks helps to Branding/advertising your company.

☛ Improve Google image search ranking

☛ Promote your business name

☛ 100% Manual Share and Publish to 70 Real PR Websites

Some of the High DA sites:

Flickr.com – DA = 98 / 100

Pinterest.com – DA = 98 / 100

Imgur.com -DA = 98 / 100

If you have no image or infographic just buy from extras.

If your choice my service, you can hire me any time.

Inbox me to learn more and order

Thanks!

.