## Does my character's controller spin without control?

I have a character controller and, after trying to implement the movement independently of the camera, it starts spinning out of control. I have no idea why. Here is the code:

Character controller:
https://pastebin.com/5sBmhUpk

CameraController:
https://pastebin.com/4vn1BZc0

## Design patterns: timer settings, when to use a combo box or spin box?

I think you will find that the decision to use one or the other input control will be based on the type of information that is required to be entered frequently.

As you can see, the turn control is ideal for smaller increments or frequent changes in input (ie, making adjustments) due to the way it is designed to allow positive or negative increments in an existing (default) value.

On the other hand, the combobox works well for smaller increments, one reason is the amount of space it occupies to show all possible values ​​and another the way in which values ​​should be selected.

Therefore, under Option 1 of your model you would probably expect to see minute increments (for example, 10, 11, 12, etc.) and for Option 2 you would probably expect to see 5 or 10 minute increments within a narrower range of values ​​(for example, 10-30min).

## at.algebraic topology – An equivalent definition for \$ text {Spin} ^ c \$ -structures

I am interested in trying the following proposition. ([G], Observation page 48):

Shore up: A $$text {Spin} ^ c$$-the structure on a vector oriented beam is equivalent (after stabilizing if the fiber dimension is odd or $$leq 2$$) to a complex structure on the $$2$$-The skeleton that can extend over the $$3$$-skeleton

The outline of the test given is as follows: First note that the inclusion $$i colon U (n) a SO (2n)$$ rises to a map $$j colon U (n) to text {Spin} ^ c (2n)$$. by $$n geq 2$$, this correspondence is bijective for $$2$$-Complex and surjectives for $$3$$-complexes, from the map. $$Bj$$ have a $$2$$-Connected fiber. The observation now follows from the fact that the restriction induces a bijection from $$text {Spin} ^ c$$-Structures to those over $$2$$-The skeleton that extends over the $$3$$-skeleton. This should conclude the test, but I am trying to understand why.

I would like to use the following diagram:

and use the induced map between the fibers. $$F, F & # 39;$$ along with the naturalness of the obstruction classes to prove that for a two-dimensional complex that has a Spin structure ^ c is equivalent to having a complex. The first thing I'm not sure about is what kind of connectivity the map has between the fiber. If that map induces an iso in the homotopy groups to the degree $$2$$ and a projection to the degree. $$3$$ The first claim must be proven. It is still not clear to me how to reach the conclusion that "the restriction induces a bijection from $$text {Spin} ^ c$$-Structures to those over $$2$$-The skeleton that extends over the $$3$$-skeleton."

Can someone help me shed some light on that?

[G] Robert E. Gompf $$text {Spin} ^ c$$-Structures and homotopy equivalences. Geometry and topology Volume 1 (1997) 41-50. (Here)

## dg.differential geometry – Existence of a certain type of compact spin collector with limit

For a compact Riemannian rotary collector $$(M ^ n, g)$$ without limit, $$n not equiv 3 mod 4$$, the Dirac operator associated with a fixed turn structure is well known. $$S rightarrow M$$ have real, discreet spectrum and symmetrical around zero If $$(M ^ n, g)$$ has a non-empty connected limit, for the Dirac operator spectrum $$D ^ S$$ of a fixed turn structure $$S$$ To be real and discreet, one has to subjugate the problem of self-worth to the Atiyah-Patodi-Singer (APS) condition. My first question is the following

Question 1. What kind of reasonable conditions (topological / geometric) do we have to impose in a compact turn? $$(M ^ n, g, partial M neq 0)$$ or $$S$$ so that the spectrum of the above mentioned. $$D ^ S$$ Restricted to the APS condition is also symmetric with respect to zero, in addition to being real and discrete?

If such a task for question 1 is possible, we will temporarily call such a variety CSymm.

Yes $$E rightarrow (M ^ n, g, partial M neq 0)$$ is any Hermitian package equipped with a compatible connection $$nabla ^ E$$. It is not difficult to see that the twisted package $$S otimes E$$ it's a Clifford package on $$M$$, in which a globally defined notion of operator of associated generalized Dirac can be had $$D ^ {S} otimes E}$$. At this point, we carefully consider a metric $$g$$ in $$M$$ so close $$partial M$$ It seems $$M times[0r)[0r)[0r)[0r)$$. With such choice of $$g$$, $$D ^ {S} otimes E}$$ has an unmistakable induced Dirac operator in $$partial M$$, denoted by $$D ^ {S} otimes E, partial}$$. We say $$(M ^ n, g, partial M neq 0)$$ is CItd If you have an Hermitian package $$(E, nabla ^ E)$$ ($$E$$ can depend on $$S$$) such that $$D ^ {S} otimes E, partial}$$ it is invertible

by $$n geq 4$$, we say $$M ^ n$$ is a good variety If and only if $$M$$ is CSymm and there is a smooth map $$f: M rightarrow mathbb {S} ^ n$$ such that $$(M, f ^ {S} S )$$ make $$M$$ a CItd manifold. here $$S_0$$ is the rotate the structure in $$mathbb {S} ^ n$$. Here is my last question

Question 2. What is an example of a good variety with positive scalar curvature?

If these questions turn out to be trivial, I would just like a clue or an intelligent observation that points me in the right direction so that I can continue on my own.

## NEW – Spin for Cash App Reviews: SCAM or LEGIT? | NewProxyLists

I made 3 offers, I got credit for them and then I deleted the applications. Then, the application removed the credits from my account even though it does not say that I should keep the application on my phone for a period of time. That's pretty bs, imo … I lost about 1k points per installation.

And I used this application for about an hour and I only managed to get about 3k points from the wheel. Also, the more you tour, the worse the delay gets. The application continued to hang and crash on my phone after turning more than 30 times in a row.

## NEW – Spin & Earn App Reviews: SCAM or LEGIT | NewProxyLists

I made 3 offers, I got credit for them and then I deleted the applications. Then, the application removed the credits from my account even though it does not say that I should keep the application on my phone for a period of time. That's pretty bs, imo … I lost about 1k points per installation.

And I used this application for about an hour and I only managed to get about 3k points from the wheel. Also, the more you tour, the worse the delay gets. The application continued to hang and crash on my phone after turning more than 30 times in a row.

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