## hard drive: Windows storage spaces that use more space than the content it contains

I am trying to understand how storage spaces work when it comes to available space in parity spaces. I set up a group, created a space and moved about 20 GiB of data. Then I deleted the data, emptied the trash and optimized the use in the Storage Spaces user interface. Currently it still shows that about ~ 50 GiBs are being used. Why is that?

Here is the storage space configuration: Storage space configuration

Here is the dialog that shows the use: Dialogue on the use of space

## python 3.x – Unwanted space characters and I can't understand why (Python3)

beginner here. Learning Python through a book called "Breaking encrypted with Python". As part of a simple encryption program, I wrote this (this is just the beginning):

``````import pyperclip

fg = lambda text, color: "33(38;5;" + str(color) + "m" + text + "33(0m"
bg = lambda text, color: "33(48;5;" + str(color) + "m" + text + "33(0m"

# Simple usage: print(fg("text", 160))

msg = input('nnEnter your secret:nn')

msg_len_int = len(msg)

msg_len_str = str(len(msg))

print('nnChoose key (has to be less than', fg((msg_len_str), 40), '): ')

key = input('nnChoose your here: ')
``````

As a result I get this:

I can't understand why I have 2 space characters that I didn't put, one before and one after `fg((msg_len_str)`.

## dg. differential geometry: \$ C ^ { infty} (M) \$ is dense in the space weighted Sobolev \$ W_ {X} ^ {1} (M) \$?

Leave $$M$$ be a compact collector without boudary and $$X_ {1}, ldots, X_ {m}$$ be the true soft vector fields in $$M$$. Consider the following weighted Sobolev space:
$$W_ {X} ^ {1} (M) = {f in L2} (M) | X_ {j} f in L ^ 2 (M) ， 1 leq j leq m }.$$
We can prove that $$W_ {1} (M)$$ It is a Hilbert space. My question is: Can we say that $$C ^ { infty} (M)$$ dense in $$W_ {1} (M)$$?

I found some results on the previous question. For a bounded domain $$Omega$$ in $$mathbb {R} ^ n$$, Meyers-Serrin theorems for associated function spaces
with a family of vector fields they were studied by N. Garofalo and D.M. Nhieu in (1), which shows that space
$$overline {C ^ { infty} ( Omega) cap W_ {X} ^ {1} ( Omega)} ^ { | cdot | W X X 1 = W X X 1 ( Omega).$$
Is this result also valid for a compact collector without boudary? Thank you!

(one) Garofalo, Nicola; Nhieu, Duy-Minh, Lipschitz continuity, smooth global approximations and extension theorems for Sobolev functions in Carnot-Carathéodory spacesJ. Anal. Maths. 74, 67-97 (1998). ZBL0906.46026.

## [Hostpoco.com]* Shared hosting @ only \$ 6 / year * AUTO SSL | Unlimited web space | MYSQL DAT

Host is also not a simple, easy, reliable and reliable web hosting service … Just register and be online in 2 minutes with our free and instant configuration!

Host also does not deal with cheap, high-resource and highly demanded web hosting services, starting at \$ 0.5 per month. All our hosting plans come with cpanel as a control panel included with some smart functions such as unlimited space, unmeasured bandwidth, free automatic ssl, free site generator, free migration service, free dedicated IP, own email address , one-click installer and much more. Hurry up!

Plan:

* shared hosting plan for beginners \$ 0.5 / monthly.

* Shared hosting plan for Pro \$ 1 / Monthly.

* Shared hosting plan for Premium \$ 2.5 / Monthly.

* Shared hosting plan for Elite \$ 5 / Monthly.

For more details :https://hostpoco.com/half-dollar-linux-s…osting.php

Characteristic:

Premium Shared Hosting Plan \$ 2.5 / Monthly:
~ Ten domain hosting
~ Unlimited web space
~ Unlimited bandwidth
~ Unlimited email accounts
~ Unlimited parked domains
~ 9 additional domains
~ Unlimited MySQL databases
~ Unlimited subdomains
~ FREE cPanel control panel
~ PHP MyAdmin FREE
~ AwStats FREE
~ FREE Auto SSL
~ FREE virus scanner
~ DDOS protection
~ 99.99% uptime
~ Softacolous supported
~ ier 3 Technical support

Hostpoco.com: budget hosting provider | Cheap hosting provider | CPanel cheap accommodation | \$ 1 unlimited hosting | Fast SSD hosting | Money back accommodation | Best selling accommodation | ideal free accommodation | free web hosting

Thank you.

## rigid body: how do I label an empty space for a boolean & # 39; InAir & # 39 ;?

I have been working with the configuration of my game to get the perfect jump height, gravity and movement that suits the player, however, my problem is that my player essentially floats to the ground, when I want them to fall much faster (It's a 3D game) but I don't want to alter gravity for the player anymore.

What I have done is create 2 additional Boolean along with my Boolean grounded, one for In Air and one for Extra Gravity, and this is where my problem comes in.

I have no idea how to set a label in the empty space in the air, and I was wondering if anyone knew how to do this, or if there is a better method to detect when my player is in the air.

This is what my script looks like now:

``````using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class PlayerScript : MonoBehaviour
{
public float movementSpeed = 5f;
public float jumpForce = 7;
public float jumpSpeed = 7;
public Rigidbody rigidbody;
private Vector3 input;
public GameObject Player;
public bool grounded;
public bool inAir;
public float ExtraGravity;

// Use this for initialization
void Start()
{
var rigidbody = GetComponent();
var col = GetComponent();
Player = GameObject.FindWithTag("Player");
}
void FixedUpdate()
{
if (Input.GetKeyDown("space"))
{

if (grounded)
{
Debug.Log("Spacebar pressed");
}

if(inAir)
{
Vector3 vel = rigidbody.velocity;
vel.y -= ExtraGravity * Time.deltaTime;
rigidbody.velocity = vel;
}

}
}

// Update is called once per frame
void Update()
{

if (Input.GetKey("w"))
{
transform.position += transform.TransformDirection(Vector3.forward) * Time.deltaTime * movementSpeed * 5.5f;
}
else if (Input.GetKey("s"))
{
transform.position -= transform.TransformDirection(Vector3.forward) * Time.deltaTime * movementSpeed * 4.5f;
}
else if (Input.GetKey("d"))
{
transform.position += transform.TransformDirection(Vector3.right) * Time.deltaTime * movementSpeed * 5.5f;
}
else if (Input.GetKey("a"))
{
transform.position -= transform.TransformDirection(Vector3.right) * Time.deltaTime * movementSpeed * 5.5f;
}

if (Input.GetKey(KeyCode.LeftShift))
{
transform.position += transform.TransformDirection(Vector3.forward) * Time.deltaTime * movementSpeed * 20.5f;
}

}

void OnCollisionStay(Collision collision)
{
if (collision.gameObject.CompareTag("Floor"))
{
grounded = true;
}
}

void OnCollisionExit(Collision collision)
{
if (collision.gameObject.CompareTag("Floor"))
{
grounded = false;
}
}

}
``````

## Receptive tables: adjust the row count to fit the available space

I am designing a screen with tabular data and trying to explain to the developers what is required. First of all, I want to make sure that my design is feasible.

My objective is …

1. Have tabular data on the screen, including filters and paging.
2. Filters should be at the top and near the header row
3. The header row should always be visible.
4. The pagination control should always be visible near the bottom row shown
5. Row height is set at 36px

So, for responsiveness, this leaves only the number of rows shown as a variable. If there is space to display only three rows while all mandatory controls are visible, only three rows will be displayed. If the same is represented on a larger screen and there is room for 25 rows, show 25. The user should always be able to expect that the mandatory controls are approximately in the same place, regardless of the size of the property.

So, do you have any examples of this that I can send to the development team?

Thank you

## algorithms: reorganize the elements to reduce fragmentation and lost space

I have a segment with some compensation at irregular intervals.

There are articles of various lengths inside. Items cannot be placed randomly. Instead, your left side should match some displacement.

Items are free to go beyond expenses.

As you can see in this image, element number 3 is long enough to go through a displacement, which is shown with a dotted line.

I also have some special type of compensation that I will call "barrier" in which the elements cannot pass and cannot be placed:

A final restriction is that the elements cannot overlap each other:

Items can be moved one at a time. So I can pick up an item and place it in another place as long as no restrictions are violated.

I am trying to find an algorithm / solver / optimizer that finds a sequence of steps good enough to reduce fragmentation and compact these elements. It follows that this procedure will reduce the empty space between the elements and the compensations:

Can you give any suggestions on how I would approach a problem like this or point me in the right direction, give some ideas, name algorithms to get inspired, etc.?

## Functional analysis: tracking and reverse tracking of second order in space with Gibbs measurement

To consider $$(t, x) in (0, T) times ( mathbb {R} ^ d, d mu)$$where the measure $$d mu (x) = K – 1 exp (-U (x)) dx$$ it is a reasonable measure of Gibbs (it satisfies an inequality of Poincaré or log-Sobolev. You can, for simplicity, start with the Gaussian $$d mu (x) = (2 pi) ^ {- frac {d} {2}} exp (- dfrac {| x | ^ 2} {2}) dx$$) We define Sobolev spaces $$L ^ 2 (I times mu) = {f: int _ { mathbb {R} ^ d} int_0 ^ T f (t, x) ^ 2 dtd mu (x) < infty }$$ Y $$H ^ 1 (I times mu) = {f: f, partial_t f, nabla_x f in L ^ 2 (I times mu) }$$ Y $$H ^ 2 (I times mu)$$ In a similar way. Now, given any $$f in H ^ 1 (I times mu)$$we can find $$u in H ^ 2 (I times mu)$$such that $$u (t = 0, cdot) = u (t = T, cdot) = 0$$ Y $$partial_t u (t = 0, cdot) = f (0, cdot), partial_t u (t = T, cdot) = f (t = T, cdot),$$ such that $$| u | _H ^ 2 (I times mu)} le C | f | H ^ 1 (I times mu)}?$$

## Cryptography: Are BTC private keys distributed evenly in a 256-bit space?

If we assume that there are ~ 2 ^ 96 private keys for EVERY bitcoin address (2 ^ 256-160) and we assume that cryptography is considered a good property of each hash function if it evenly distributes the values ​​in its codomain (the function's domain SHA256 is the domain of RIPEMD160).

Does that mean that HALF of the ~ 2 ^ 96 private keys is in the first 2159 and another HALF is in the space 2 ^ 160 – 2 ^ 256?