Change column position using JSON sharepoint online

Is it possible to change the positions of the columns in a JSON template? I have ordered them within the JSON file, but once the template runs the default sharepoint columns still show in the original position.

Example

I would like Version column to appear first, Name column to appear second, and Program column to appear third.

Need help with CSS image position and background color

Hi i’m trying to move the black dove image to somewhere in the green header background. I tried using position relative, absolute together with margin, padding can’t seems to figure out how to push it there. You can download the HTML file here https://github.com/mdn/learning-area/blob/master/html/introduction-to-html/structuring-a-page-of-content-start/assets.zip?raw=true

The first that contains h1, this is my CSS:

text-align: center;

height: 300px;

font-family: ‘Cinzel Decorative’, cursive;

clear: right;

background-color: #32CD32

}

For the dove.png image tag, this is my CSS:

width: 150px;

height: 120px;

float: right;

}

I want to move the dove image into the green background header. Example here the dove is on the top right: https://media.prod.mdn.mozit.cloud/attachments/2016/02/09/12449/7591b0b929e32f5164d3496229799255/example-page.png

Also the background color for header is not occupying the entire browser screen for that div, can someone advise me on how to do both? thanks.

Simples creio….

Dois containeres, um posicionado absolutamente em relaçao ao outro.Como mensurar o espaço ocupado por este primeiro, para q os blocos subsequentes respeitem o fluxo sob o espaçamento definido? Em outras palavras, como atribuir um valor estatico a um elemento posicionado com valor absoluto?

Nesse caso o element é posicionado relativamente à sua origem, q "segura" ou "afasta" o bloco subsequente, mas o raciocinio para a resolucao do problema se mantem.

How to find the smallest position of an element of an ascending list {1,4,10,12,20} such that the element is not less than 11?

Assume I have an ascending list `{1,4,10,12,20}`.
I want to find the smallest position of an element of the list such that the element is not less than 11?
The position in question is 4.

How to do this easily?

Set menu position why theme inactive

I need to switch a theme to it’s copy with some modifications, but when I do so, the position of the menus need to be selected again. There must be a way to set this in tha database while the theme is inactive, so that switching a theme is smooth.

plotting – How-to position ContourLabel outside the Frame and Overlay ArrayPlot with ListContourPlot

This is a follow-up to the question I have left earlier today. Now, thanks to @kglr I made some progress on my mini project. This said, there are still a few things that I want to do with it, and I can’t seem to find a solution myself, here on stackexchange.

Here is the updated code…

``````(* work-in-progress *)
data3 = Outer({#1, #2, #1*#2} &, Subdivide(.02, 1, 4),
Subdivide(10000, 10^7, 4)) // Flatten(#, 1) &
grid = Reverse @ {
{Green, Green, Green, Yellow, Yellow},
{Green, Green, Yellow, Yellow, Orange},
{Green, Yellow, Yellow, Orange, Orange},
{Yellow, Yellow, Orange, Orange, Red},
{Yellow, Orange, Orange, Red, Red}
};

Overlay({
ArrayPlot(
grid
, Mesh -> All
),
ListContourPlot(
data3
, Frame -> True
, Contours -> {300000, 600000, 900000, 1600000, 2200000}
, ContourStyle -> {{Thick, Dashed, Black}}
, ContourLabels -> (Text(Framed(#3), {#1, #2},
Background -> White) &)
, ScalingFunctions -> {None, "Log10"}
)
})
``````

It produces the following plot…

Now, I would like to overlay the `ListContourPlot` over the `ArrayPlot`. However, it seems like I am getting some misalignment which I can’t seem to fix. I would also like to move the `ContourLabels` at the right side of the frame near their designated contours. I have tried a few things but also failed to achieve the desired effect. I would appreciate your help, any help would be great!

algorithms – Find position in array where element-wise multiplication with string of 1 and 0s results in max value

I have a sequence of 1s and 0s. For example: $$bits = (1, 0, 1, 1, 1, 0)$$. I also have an array of positive integers. For example $$arr = (12, 23, 4, 6, 8, 0, 24, 72)$$. I need to find the index, $$i$$, in $$arr$$ of the leftmost element of $$bits$$ such that

$$sum_{j = i}^{i + textrm{length of bits}}{bits(j – i) * arr(j)}$$

is a maximum. Essentially I am maximizing the element-wise multiplication between the two sequences starting at index $$i$$.

I need to solve it in $$O(nlog n)$$ or better, but I can only think of a way to do it in $$O(n^2)$$. I have a feeling prefix sums could be used but am not sure how.

Jack of all trades vs master of one, and terrain

Emergency Locator Transmitters are marvelous things, but the infrastructure to support a truly excellent one is fantastically expensive. As such, the world actually got together on something, and built one system called the 406 MHz ELT. Everyone uses it – ships at sea, jetliners, and hikers willing to throw down the ~\$350 for a transmitter able to share the playfield with 747’s. There’s a jointly run NOC that knows how to reach all the world’s emergency responders, from the Eritrean Coast Guard to CalFire. This system was conceived in the 1980s, so it doesn’t think about mundane uses like tweeting, and in fact is not 2-way.

The 406 system has one job and one use. It has a long life, one-shot battery, so it doesn’t need to be occasionallly charged like a normal electronic device.

There is a private effort called SPoT, which is less optimized to be an ELT and more optimized to be a social media toy. It uses the Iridium sat phone network, which is intended for satellite phones not emergency locators. As such, Spot’s coverage is poorer than the dedicated 406 MHz ELT network. By “poorer” I mean ability to function in valleys and canyons, and also ability to communicate with more obscure emergency services.

However, because SPoT is rooted in newer 2-way system, it has some bells and whistles the 406 MHz system does not have. It hourly logs your location, creating a “breadcrumb” log of your route (when able to communicate) or when commanded by the user. And of course, it has its primary function of 2-way messaging, which you can do anytime you have signal.

SPoT is also a pay service, which means you must have it paid up, and it has an ordinary rechargeable battery that must be recharged every few months at least. You can,t just stick it in your glove box for a rainy day.

This equipment can also be rented. Emergency responders call the owner, who states who they rented it to. (Of course that’s a link in the chain!)

This is a corner case, though

Because he was in a crevasse, he’s more likely to get signal from a 406 MHz ELT than a SPoT, but realistically there’s a fair chance he wouldn’t get signal for either one of them. In that case, each of them would contribute something different.

• SPoT would contribute the “breadcrumb” locations from the hours before, which would get them within a couple kilometers. That’s if authorities could associate his 911 call with his SPoT account – and that’s a big if!
• the 406 MHz ELT has a second trick: it transmits a tone on the 121.5 MHz emergency frequency, which is an older, pre-satellite emergency location system designed to direct terrestrial rescue efforts. It is used and monitored (not least by passing airliners) and emergency services are well-practiced at triangulating on signals from it. Ideally, 406 gets them in the neighborhood and 121 brings them home. There’s also a chance his tone would be heard organically, even with a 406 failure due to terrain. If he had specifically said on the cell phone that he’d activated an ELT, they surely would have sent a plane up and down the coast to listen. They would have triangulated quickly, between the tone and the verbal description “I can see the ocean”.

Again, this is a corner case. On an average activation, especially assuming terrain is involved, the 406 is better than the SPoT, and certainly works more places in the world (because the 406 NOC is better equipped to reach relevant authorities).

I am also concerned with cases like James Kim. SPoT requires you keep a subscription paid up and a typical smart-device battery recharged. If either of those is let to slide, SPoT is worthless. A 406 can be thrown under the car seat with the flares and poncho, and forgotten about for several years.

python – How Do I make My Sprite Aim At The Player Any Position The Player Is At? Pygame

so I have a function here called Lookat() that suppose to aim at the player but how can I call the Lookat() function on my main loop to make it aim at the player like how could I get the position? and call it because my position of my player sprite will be updating each time VIDEo I am trying to make the cannon rotate towards the player just like how my bullets are aiming at the player

``````class enemyshoot:
def __init__(self, x, y, height, width, color):
(...)
# Make a Reference Copy of the bitmap for later rotation
self.image    = self.original
self.rect     = self.image.get_rect()
self.position = pygame.math.Vector2( ( x, y ) )

def lookAt( self, coordinate ):
# Rotate image to point in the new direction
delta_vector  = coordinate - self.position
self.image    = pygame.transform.rotozoom( self.original, -angle, 1 )
# Re-set the bounding rectangle and position since
# the dimensions and centroid will have (probably) changed.
current_pos      = self.rect.center
self.rect        = self.image.get_rect()
self.rect.center = current_pos

$$```$$
``````

performance tuning – Best way to insert element into an ordered list at the correct position?

Suppose I have an ordered list `orderedList` and I want to write some code that will involve regularly inserting new elements into `orderedList` in the correct positions, according to the ordering. One possibility is

`Sort[AppendTo[orderedList,x]]`,

but this is inefficient because Mathematica doesn’t know `orderedList` is already ordered, hence it will waste time verifying that the original elements of `orderedList` are already ordered.

Another idea is to use `SelectFirst` to obtain the proper position at which to insert `x`, via

`Insert[orderedList,x,FirstPosition[SelectFirst[orderedList,#>x&]]]`.

The trouble here is that since Mathematica doesn’t know `orderedList` is ordered, its `SelectFirst` algorithm will use a linear search rather than binary. Also, the requirement of using `FirstPosition` will double the computation time.

So what is the “right” way to do this, i.e., what method inserts an element into an ordered list without wasting resources?