## networks – limit the maximum UDP bandwidth per IP using iptables?

I am using a VPS to host a VPN for DDoS protection, but I have been looking for a way to limit UDP traffic over IP to avoid UDP floods. I am looking for something to allow only X MBPS of traffic to each IP, and ignore this IP if its traffic exceeds X MBPS

Mainly I want to prevent DoS from having perl / shell scripts, since these seem to be effective in interrupting the operation of the VPN

it's possible?

If so, could someone help me with a method to implement this using iptables?

## Without magic, 600 feet, a sniper with a long bow

A long arc has a range of 150/600 feet, and the feat Sharpshooter (. PHB, p 170) includes this benefit:

Long-distance attack does not impose disadvantages on your ranged weapon attack rolls.

This means that you can perform a ranged attack against a target of up to 600 feet without disadvantage. I don't know any class or similar characteristics that allow you to increase the range of your ranged weapon attacks. This would be "always on", as long as it has arrows.

## With magic, 2 miles, a master magician / sorcerer in the know with the distant metamagic spell that casts any distant spell

This article introduced the arcana Arcana disinterred tradition of Lore Mastery for wizards, including the following feature class:

Alchemical Foundry On the sixth level, you learn to increase spells in several ways. When you cast a spell with a spell space, you can spend an additional spell space to increase its effects for this cast, mixing the magical raw material in your spell to amplify it. The effect depends on the spell space you spend.

(…)

An additional second level spell space can increase the spell's range. If the spell's range is at least 30 feet, it becomes 1 mile.

Any remote spell with a range of at least 30 feet, say fire bolt, then you can make a distance attack roll to a target up to a mile away, assuming you have a clear path to the target and a way to see them at that distance (for example, by multiclassing in Totem Barbarian to get the Eagle from level 6 totem). This works as long as you have second level spell spaces remaining.

If you multiclassified in sorcerer to get the spell metamagia away, it says:

### Distant spell

When you cast a spell that has a range of 5 feet or more, you can spend 1 point of sorcery to double the range of the spell.

This can be doubled to 2 miles. This is possible only if you have sorcery points to spend on metamagia.

## Alternatively, with magic, 2 miles and 20 feet, Sorcerer with distant spell metamagia or any spellcaster with Spell Sniper feat casting meteor swarm

If we don't need it to be an attack roll specifically, then meteor swarm It has a range of 1 mile and affects a radius area of ​​40 feet, so if launched at a maximum distance, it could damage a target that is 1 mile and 20 feet from the launcher.

Then, I could increase this range to 2 miles, either by using the distant spell metamagia mentioned above, or by having the spell sniper feat (PHB, p. 170), which says:

When you cast a spell that requires a ranged attack roll, the range of the spell doubles.

Doubling the spell's range allows you to damage a target up to 2 miles and 20 feet away. This is possible only if you have level 9 spell slots to use and spell points to spend on metamagia (if you go with that option to double the distance; the Spell Sniper feat, however, is "always active") .

## Without magic, 600 feet, a sniper with a long bow

A long arc has a range of 150/600 feet, and the feat Sharpshooter (. PHB, p 170) includes this benefit:

Long-distance attack does not impose disadvantages on your ranged weapon attack rolls.

This means that you can perform a ranged attack against a target of up to 600 feet without disadvantage. I don't know any class or similar characteristics that allow you to increase the range of your ranged weapon attacks. This would be "always on", as long as it has arrows.

## With magic, 1 mile, a Lore mastery wizard with any remote spell

This article introduced the arcana Arcana disinterred tradition of Lore Mastery for wizards, including the following feature class:

Alchemical Foundry On the sixth level, you learn to increase spells in several ways. When you cast a spell with a spell space, you can spend an additional spell space to increase its effects for this cast, mixing the magical raw material in your spell to amplify it. The effect depends on the spell space you spend.

(…)

An additional second level spell space can increase the spell's range. If the spell's range is at least 30 feet, it becomes 1 mile.

Any remote spell with a range of at least 30 feet, say fire bolt, then you can make a distance attack roll to a target up to a mile away, assuming you have a clear path to the target and a way to see them at that distance (for example, by multiclassing in Totem Barbarian to get the Eagle from level 6 totem). This works as long as you have second level spell spaces remaining.

## Alternatively, with magic, 2 miles and 20 feet, sorcerer meteor swarm

If we don't need it to be an attack roll specifically, then meteor swarm It has a range of 1 mile and affects a radius area of ​​40 feet, so if launched at a maximum distance, it could damage a target that is 1 mile and 20 feet from the launcher. If you are a sorcerer with the metamagia of the spell away, it says:

### Distant spell

When you cast a spell that has a range of 5 feet or more, you can spend 1 point of sorcery to double the range of the spell.

Then you could increase this range to 2 miles, being able to damage a target up to 2 miles and 20 feet away. This is possible only if you have slots Level 9 spells to use and Wizardry points to spend on metamagic.

## seo – How can I calculate the maximum and minimum monthly budget in AdWords?

I couldn't find it anywhere, so you are my last hope.

Let's say I have the average monthly searches, competition, offer from the top of the page (low rank) and offer from the top of the page (high rank) and also% 10 CTR for a keyword.

How can I calculate the maximum and minimum monthly budget for that keyword?

## real analysis: dual standard of a maximum function

I am trying to find the double standard of
$$| (x, y) | _K = max {| x |, | and |, | x-y | }.$$
I have obtained $$| (x & # 39 ;, y & # 39;) | _K ^ * = | x & # 39; | + | and & # 39; |$$, but don't think that this is correct.
I got this as follows:
$$K = {(x, y) en R ^ n: max {| x |, | and |, | x-y | } leq 1 }$$
$$| (x, y). (x & # 39 ;, and & # 39;) | = | xx & # 39; + aa & # 39; | leq | x || x & # 39; | + | and || and & # 39; | leq max {| x-y |, | x |, | and | } (| x & # 39; | + | y ​​& # 39; |) leq | x & # 39; | + | and & # 39; |,$$
concluding so that $$| (x & # 39 ;, y & # 39;) | _K ^ * = | x & # 39; | + | and & # 39; |$$.
I don't think this is correct because I know that this is the double standard of $$max {| x |, | and | }$$. What is the correct dual standard?

## real analysis: find the maximum of a restricted function

Leave $$f (x, y, z): = z ^ 4 (x ^ 2 −xy + y ^ 2) + z ^ 2 (x ^ 4 + y ^ 4)$$
and let A ⊂ R3 be the convex polyhedron with vertices (1, 0, 0), (0, 2, 0), (0, 0, 3) and (4, 4, 0). Find $$sup_A f$$.

I understand how to use lagrange multipliers in constraints and limits and I have to verify if the Jacobian matrix includes 0 or is not correct. but I'm not sure how to apply here. Thank you.

## windows – My Laptop 2 – 1 keeps the volume of silence and maximum on the speakers

I have a Dell Inspiron 5378 and it is a 2 in 1. The volume worked normally so far. I had to catch up with a lot of updates and once I did, the problem didn't go away. When I am in computer mode, the volume is muted and when I try to increase it, it is muted. And then, when I'm in tablet mode, the volume continues to reach 100% and when I try to lower it, it reaches 100%. I've tried the usual thing ("Do nothing" in communications call setup and uninstall / reinstall Realtek drivers. "), But I could have done it wrong. I'm on an Intel-based laptop and I'm running Windows 10.

## Formal languages: maximum number of Turing machine configurations after \$ n \$ movements

I found the following question:

What is the maximum number of Turing Machine settings after $$n$$ movements?

$$k ^ n$$, where $$k$$ It is a branching factor.

And that "branching factor" left me confused. Then I thought: given $$Q$$ be the total number of states, $$Gamma$$ be a ribbon alphabet and two movements, left and right $${L, R }$$, for each transition function, we have $$2 ^ {times Gamma times 2}$$ possible transitions in each of those $$n$$ moves like this, $$k$$ must be $$2 ^ {times Gamma times 2}$$. Then, the total number of Turing machine settings after $$n$$ the movements must be $${(2 ​​^ {times Gamma times 2})} ^ n$$. Am I correct with this?

## Find peaks, maximum and minimum of an interpolation function?

I am new to math.

I have a list of values ​​and I don't know how to find some poitns, such as peaks, the maximum and the minimum of an interpolation function.

RA = List [{0, 0.727578}, {0.4, 0.73179}, {0.8, 0.773248}, {1.2, 1.342248}, {1.6, 0.987746}, {2, 0.791317}, {2.4, 1.11788}, {2.8, 0.996614 }, {3.2, 0.938749}];

f = Interpolation [RA]

Interpolation function [{{0., 3.2}}, <>]

Thank you

## co.combinatorics: expected value of the maximum distance between neighbors in permutations

For any positive integer $$n$$, leave $$(n): = {1, ldots, n }$$. Leave $$S_n$$ denote the set of permutations (bijections) $$pi: (n) a (n)$$. For any $$n> 1$$ Y $$pi in S_n$$ we let the maximum distance of neighbors be defined by $$text {mnd} ( pi) = max big ( { | pi (k) – pi (k + 1) |: k in (n-1) } cup {| pi (n) – pi (1) | } big). PS$$
by $$n> 1$$ we denote by $$E_n$$ the expected value of $$text {mnd} ( pi)$$ where $$pi$$ extends over $$S_n$$.

Is $$lim_ {n to infty} frac {E_n} {n}$$ defined, and if so, what is its value?