How to increase the maximum limit of macOS Catalina process (version 10.15.1)

I tried to increase my MacBook Pro process limit and the file limit. I was able to increase the file limit but not process. I followed this blog to do that.

▶ ulimit -a
-t: cpu time (seconds)              unlimited
-f: file size (blocks)              unlimited
-d: data seg size (kbytes)          unlimited
-s: stack size (kbytes)             8192
-c: core file size (blocks)         0
-v: address space (kbytes)          unlimited
-l: locked-in-memory size (kbytes)  unlimited
-u: processes                       4176
-n: file descriptors                65536

As you can see above file descriptors it increased but no processes.

Can we do that or is there any restriction of the operating system (macOS Catalina)?

category theory: it is the direct limit created by the forgetful functor of an algebra of Eilenberg-Moore

Proposition. Leave $ T $ be a monad in $ C $ and consider the
Forgetful Functor
$$
R ^ T colon C ^ T to C
$$

from the category of algebras of Eilenberg-Moore to $ C $. This functor

  • create limits;
  • create colimits that are preserved by $ T $ Y $ T ^ 2 $.

A noticeably stronger condition for a colimit is to be absolute,
that is to say. preserved by each functor.
An intermediate condition (random?) Must be preserved for each
endofunctor

I have an example in mind of a functor that is created: direct limits
(also known as colimits under directed diagrams) by the forgetful functor
$$
U colon operatorname {Ring} to operatorname {Set}.
$$

Question: they are direct limits on the set preserved by

  1. the monad associated with the complement with rings,
  2. every monad
  3. each endofunctor,
  4. each functor?

In more general terms, can I expect to show that any direct limit
(also known as colimit under directed diagam)
is created by the forgetful functor of any algebra of Eilenberg-Moore
through the previous proposition?

pr.probability: is there a lower limit in the opposite direction to the inequality of data processing?

Leave $ f_1 $ Y $ f_2 $ be the random variable distributions $ X_1 $ Y $ X_2 $ respectively. Leave $ g_1 $ Y $ g_2 $ be the distributions of $ T (X_1) $ Y $ T (X_2) $ respectively where $ T ( cdot) $ It is some function. For any divergence f, $ D_ {f} ( cdot | cdot) $, inequality in data processing gives us $$ D_ {f} (g_ {1} | g_ {2}) leq D_ {f} (f_ {1} | f_ {2}). $$ Is there any known result in the opposite direction in the form? $ D_ {f} (g_ {1} | g_ {2}) geq h (D_ {f} (f_ {1} | f_ {2})) $ for some function $ h ( cdot) $?

cv.complex variables – Pseudo-holomorphic disk that is constant along the limit

Leave $ (M, J, omega) $ be a symplectic multiple with a compatible almost complex structure, $ D $ be the drive disk closed in $ mathbb {C} $Y $ u: (D, i) a (M, J) $ be a $ (J, i) $-Homomorphic map.

Question: Assume $ u | _ { partial D} $ it's constant does this imply $ u $ Is it a constant map?

calculation and analysis – Limit in infinity

My code:

a = 1.26957; k = 0.607248;
tailF(x_) := Exp(-a*x^k);
m = 1; b = 3;
f(x_) := (m*(2*π*b*x^3)^(-0.5))*Exp(-((x - m)^2)/(2*b*x));
mesi = N(Integrate(x*f(x), {x, 0, Infinity}));
diaspora = N(Integrate(x^2*f(x), {x, 0, Infinity}) - (Integrate(x*f(x), {x, 0, Infinity}))^2);
ouraF(x_) := Integrate(f(t), {t, x, Infinity});
N(Limit(ouraF(x)/tailF(x), {x, Infinity}))

I am doing something wrong when I calculate the limit. The denominator has an Integrate and its problem is how I can express it.

Is there a limit to how long an if statement can be in Java?

I was working on a game called the game L. In the function to verify a victory, I had an if statement like this:

if (buttons(i)(0).getText().equals(colour)  || buttons(i)(0).getText().equals("0") && buttons(i)(1).getText().equals(colour)  || buttons(i)(1).getText().equals("0") && buttons(i)(2).getText().equals(colour)  || buttons(i)(2).getText().equals("0") && buttons(i+1)(2).getText().equals(colour)  || buttons(i+1)(2).getText().equals("0") && !(buttons(i)(0).getText().equals(colour) && buttons(i)(1).getText().equals(colour) && buttons(i)(2).getText().equals(colour) && buttons(i+1)(2).getText().equals(colour))) {
        return false;
}

And this code did not work. Not that I received a mistake, I just wasn't doing what I was supposed to do when a player won. However, it changed to a few if statements with each other like this:

if (buttons(i)(0).getText().equals(colour)  || buttons(i)(0).getText().equals("0")) {
    if (buttons(i)(1).getText().equals(colour)  || buttons(i)(1).getText().equals("0")) {
        if (buttons(i)(2).getText().equals(colour)  || buttons(i)(2).getText().equals("0")) {
            if (buttons(i+1)(2).getText().equals(colour)  || buttons(i+1)(2).getText().equals("0")) {
               if (!(buttons(i)(0).getText().equals(colour) && buttons(i)(1).getText().equals(colour) && buttons(i)(2).getText().equals(colour) && buttons(i+1)(2).getText().equals(
                    return false;
                }
            }
        }
    }
}

And this works.

A randomized central limit theorem

Leave $ X_k $, $ k = 1, 2, points $, be a sequence of i.i.d. random variables with second finite moments. Also leave $ N_k geq 1 $, $ k = 1, 2, points $, be a sequence of random variables that take integral values, so that $ lim_k N_k = infty $ a.s .. Also, suppose that each $ N_k $ is independent of the $ X_k $& # 39; s.

Yes $ S_k: = sum_1 ^ {N_k} X_k $, it follows that $ (S_k – mu N_k) / sigma sqrt {N_k} $ converges in distribution to the standard normal variable
(where $ mu = mathbb {E} (X_k) $ Y $ sigma ^ 2 = mathbb {V} (X_k) $) how $ k to infty $?

differential equations: the NDSolve value of MMA cannot be used to solve finite element problems according to the voltage limit conditions

the NDSolvevalue MMA can solve finite element problems well according to displacement limit conditions

(*FEMDocumentation/tutorial/SolvingPDEwithFEM*)

  (CapitalOmega)=RegionDifference(Rectangle({-1,-1},{1,1}),Rectangle({-1/2,-1/2},{1/2,1/2}));
op={-Derivative(0, 2)(u)(x, y) - Derivative(2, 0)(u)(x, 
    y) - Derivative(1, 1)(v)(x, y), 
  -Derivative(1, 1)(u)(x, y) - Derivative(0, 2)(v)(x, 
    y) - Derivative(2, 0)(v)(x, y)}

Subscript((CapitalGamma), D)={DirichletCondition({u(x,y)==1.,v(x,y)==0.},x==1/2&&-1/2<=y<=1/2),DirichletCondition({u(x,y)==-1.,v(x,y)==0.},x==-1/2&&-1/2<=y<=1/2),DirichletCondition({u(x,y)==0.,v(x,y)==-1.},y==-1/2&&-1/2<=x<=1/2),DirichletCondition({u(x,y)==0.,v(x,y)==1.},y==1/2&&-1/2<=x<=1/2),DirichletCondition({u(x,y)==0.,v(x,y)==0.},Abs(x)==1||Abs(y)==1)}
{ufun,vfun}=NDSolveValue({op=={0,0},Subscript((CapitalGamma), D)},{u,v},{x,y}(Element)(CapitalOmega),  StartingStepSize->0.1,MaxStepSize->0.01, WorkingPrecision->30,InterpolationOrder->All, NormFunction->(Norm(#, 1)&))
ContourPlot(ufun(x,y),{x,y}(Element)(CapitalOmega),ColorFunction->"Temperature",AspectRatio->Automatic,PlotPoints->30,WorkingPrecision->20,Contours->30)

enter the description of the image here

But the ndsolve value of MMA cannot be used to solve finite element problems according to the voltage limit conditions

  Clear("Gloabal`*")
(CapitalOmega) = 
  RegionDifference(Rectangle({-1, -1}, {1, 1}), 
   Rectangle({-1/2, -1/2}, {1/2, 1/2}));

op = {Derivative(1, 0)((Sigma)x)(x, y) + 
   Derivative(0, 1)((Tau)xy)(x, y), 
  Derivative(0, 1)((Sigma)y)(x, y) + 
   Derivative(1, 0)((Tau)xy)(x, y), 
  Derivative(2, 0)((Sigma)x)(x, y) + 
   Derivative(0, 2)((Sigma)y)(x, y) + 
   2*Derivative(1, 1)((Tau)xy)(x, y)}
(*(PartialD)Subscript((Sigma),xx)(x,y)/(PartialD)x+(PartialD)
Subscript((Tau),xy)(x,y)/(PartialD)y(Equal)0 (PartialD)Subscript(
(Sigma),yy)(x,y)/(PartialD)y+(PartialD)Subscript((Tau),xy)(x,y)/
(PartialD)x(Equal)0*)
Subscript((CapitalGamma), 
  D) = {DirichletCondition({(Sigma)x(x, y) == 10., (Sigma)y(x, y) ==
      0., (Tau)xy(x, y) == 0.}, 
   Abs(x) == 1/2 && -1/2 <= y <= 1/2 || -1/2 <= x <= 1/2 && 
     Abs(y) == 1/2), 
  DirichletCondition({(Sigma)x(x, y) == -10., (Sigma)y(x, y) == 
     0., (Tau)xy(x, y) == 0.}, Abs(x) == 1 || Abs(y) == 1)}

(*{ufun,vfun,wfun}=NDSolveValue({op(Equal){0,0,0},Subscript(
(CapitalGamma),D)},{(Sigma)x,(Sigma)y,(Tau)xy},{x,0,5},{y,0,1},
Method(Rule){"PDEDiscretization"(Rule){"MethodOfLines",{
"SpatialDiscretization"(Rule)"FiniteElement"}}})*)
{ufun, vfun, wfun} = 
 NDSolveValue({op == {0, 0, 0}, 
   Subscript((CapitalGamma), 
    D)}, {(Sigma)x, (Sigma)y, (Tau)xy}, {x, 
    y} (Element) (CapitalOmega), StartingStepSize -> 0.1, 
  MaxStepSize -> 0.01, WorkingPrecision -> 20)
ContourPlot(ufun(x, y), {x, y} (Element) (CapitalOmega), 
 ColorFunction -> "Temperature", AspectRatio -> Automatic)

enter the description of the image here

The result of this image is obviously incorrect.

security – How to restrict python os.listdir () to a list to a certain limit

In short: how can I restrict the python? os.listdir( ) such that I can't use os.listdir( ) beyond a specific folder.
For example:

Consider the structure of the directory:

- A
  | - B
  |   | - L
  |   | - M
  |
  | - C
      | - Secret.txt

Suppose I am in yes so how can I restrict the you not to listdir from A or C using os.listdir('../') or os.listdir('../C/')??

Features – How can I limit my Wp theme to a single site?

I created my first wp theme and I want to use it alone, I would not like any other person (wp site) to use it even though they got it by chance,

Please, is there any way I can put some kind of feature by which the wp theme will not work when the user has not activated it …