calculation – improper integral use comparison theorem

I have to determine using the comparison theorem if the following integral rather converges or diverges:

$$ int_0 ^ infty frac { ln {x}} {x ^ 2} dx $$

It is evident that this tintegral is improper because the upper limit goes to infinity and is asymptotic in $ x = 0 $. Then I split it into two parts:

$$ int_0 ^ infty frac { ln {x}} {x ^ 2} dx = int_0 ^ 1 frac { ln {x}} {x ^ 2} dx + int_1 ^ infty frac { ln {x}} {x ^ 2} dx $$

Of course, the first part has a negative sign and the second, a positive sign.

So, is it possible to determine with the comparison theorem the nature of the integral? In that case, what are the functions to compare?

Also, is it possible that the negative area can be canceled by the positive area?

calculation and analysis: how to prove that an improper integral converges or diverges?

Verify the improper integral. $ int_ {1} ^ { infty} x cdot left | sin (x ^ 4) cdot without x right | $ dx converge or diverge, I code

To integrate[x*Abs[Sin[x^4]*Sin[x]]{x, 1, infinity}

then feedback is the expression of $ int_ {1} ^ { infty} x cdot left | sin (x ^ 4) cdot without x right | $ dx.It means the improper integral $ int_ {1} ^ { infty} x cdot left | sin (x ^ 4) cdot without x right | $ dx converge?

Is there a $ n in mathbb {N} $ such that the Riemann integral improper $ int_0 ^ { infty} | sin (x ^ {n}) | $ converge?

I know that $ int_0 ^ { infty} sin (x ^ { alpha}) $ converge for $ | α | geq 1 $ that can be attributed to the cancellation of areas and $ int_0 ^ { infty} | sin (x ^ { alpha}) | $ diverges for $ n = 2 $ Since there is no cancellation of areas. It seems unlikely, but maybe there is a $ n $ So that the area of ​​oscillations can be made so small that it can be approximated by a geometric series?