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How to toggle between two custom fields in the add-in & # 39; WC Product Field Group & # 39; WordPress woocommerce?

I have a full suit that adapts the WordPress website and I use it with the woocommerce plugin. I need 2 groups of custom fields to display on a single product page.

  1. Custom measurements (accurate)
    In this method, the customer has to measure and enter all the data, such as height, weight, etc.

  2. Standard sizes (fast)
    This is the world standard size. Small, medium, large, etc.

I have created 2 groups of custom fields and they are only visible with & # 39; Product category name & # 39;

I need to alternate between these 2 field groups when a customer selects their interested 1 or 2 measurement method.

I don't have a good knowledge of PHP, so if possible, I prefer some easy method to do it.

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sql server – Availability group notification when adding a new database

When a new database is added to the SQL Server AG configuration, a notification email is sent to us as follows.

The database of the availability group "XXXX" is changing the roles from "SECONDARY" to "SECONDARY" because the duplication session or the availability group failed due to role synchronization. This is just an informational message.

What is confusing is the phrase.

"Change roles from" SECONDARY "to" SECONDARY "…"

  1. Can anyone decode the meaning of this?
  2. Is it normal for such a notification to be sent when new databases are added or am I doing it wrong or any other problem?

–In & # 39; thoughts & # 39; …

Rt representation theory: representations of the symmetric group of subgroups

Consider the finite symmetric group in $ n $ letters $ S_n $ Y $ chi $ a representation in a complex vector space of finite dimensions $ V $. Also, suppose you know the dimension of the invariant sub-vector space $ I $ from $ V $. To know how to decompose $ chi $ in irreducible representations of $ S_n $, this already gives us some information. Yes $$ chi = sum_ {i = 1} ^ {p (n)} a_i T_i $$ is the decomposition of $ chi $ in irreducible with $ T_1 $ being the trivial representation, we have $$ dim V = sum a_i dim T_i $$ Y $$ a_1 = dim I. $$ Now consider the set of conjugation classes of $ S_n $, which we denote by $ {C_i } $. Choose an item $ c_i $ in each conjugation class, and consider the group generated by it, which we denote by $ Z_i $. Restricting $ chi $ to each $ Z_i $, we get a $ Z_i $ representation in $ V $. Suppose you also know the dimension of the invariant sub-vector space $ I_i $ for each $ Z_i $. With this we can get a lot of new equations, since $ dim I_i $ it has to be equal to the trivial representation coefficient of $ Z_i $ when we restrict $ chi $ the.

So my question is this: is this information enough to deduce all the $ a_i $that is, the decomposition of $ chi $ in irreducible? In principle we are producing $ p (n) + $ 1 equations, so it should be enough if they form a basis of the vector space of dimension $ p (n) $. I have done the calculations up $ n = $ 6, and works. In fact, I am quite convinced that this works for everyone. $ n $, but I could not present a test … Any help would be greatly appreciated!

Sharepoint online: how to find out if there is a current user in a group

I need to find out if a user is in a group. If so, it could show or hide properties.

I have the following code, can it be used or adapted to find out if a user is in a & # 39; group of administrators & # 39 ;?

let grupy = sp.web.currentUser.groups.getByName("Właściciele witryny Portal UAM").users;
console.log(grupy);

One question is about the properties and the second is about the current registered user.

javascript – How to get the email address of the users of the person or group field – using CSOM

To obtain the user's email address or username, you must use web.ensureUser() method and then get the email or login name as follows:

Example:


Reference: Retrieve the size and email of the person or group list field in SharePoint
.

Solution for you:

Then, for your case, you can use its function in this way:

function FunctionToReturnEmailAddress(employeeName) {
    var user = clientContext.get_web().ensureUser(employeeName);
    clientContext.load(user);

    clientContext.executeQueryAsync(
        function(){ 
            // successfully ensured user from user name
            var email = user.get_email();
            var login = user.get_loginName();
            var displayName = user.get_title();
            alert("User LoginName: " + login + "nUser Email: " + email + "nUser Display Name: " + displayName);
        },function(sender,args){ // on error
            alert(args.get_message());
        }
    );
}

Use:

FunctionToReturnEmailAddress(employeeName);

2013 – Hide field in the form of Infopath based on User Group

You can hide fields based on the SharePoint group membership in the InfoPath form. Check if the current user is a member of a group, then hide the fields if the current user is not in the group.

In the form, use GetUserProfileByName (SOAP web service: http://contoso.com/_vti_bin/UserProfileService.asmx) and GetUserCollectionFromGroup (SOAP web service: http://contoso.com/_vti_bin/UserGroup.asmx) Current user is in the specific group. If the current user is not a member of the "Hub Group" group, hide the sections to which the user does not have access.

A demonstration on how to verify if a user is a member of a SharePoint group in InfoPath:

How to: check if a user is part of a SharePoint group in a web-based InfoPath form

A blog on how to use the InfoPath data connection to create rules for hiding / disabling fields based on the current user's SharePoint group membership. Although the links are for InfoPath 2010, they should still have good information.

Information path list form: hide / disable fields based on SharePoint group membership

Or we can use the JavaScript code to achieve it. See the article below.

Show or hide form fields based on membership in a SharePoint group

dnd 5e – How many people need to succeed in a group check with three people?

You have cited all the necessary rules for this. You put them together like this:

To do a group skill check, everyone in the group does the skill check. If at least half of the group succeeds, the entire group succeeds. Otherwise, the group fails …

Well, we need & # 39; half & # 39; of the group to succeed. What does "half" mean? In 5e we use normal language unless the book tells us to do something strange. In this case, as he quoted, the book make Tell us to do something weird instead! He says:

Whenever you divide a number in the game, round down if you end up with a fraction, even if the fraction is half or more.

So while half of 5 usually be 2.5, in this game it is 2. Similarly, when one applies these rules to the number & # 39; 3 & # 39; you can see that, because & # 39; 3 & # 39; It is an odd number, reducing it in half makes it end with a fraction. That means you round down and end up with the next whole number down, in this case & # 39; 1 & # 39 ;. Similarly, if you cut 1 by half, it would end with 0.


Keep in mind, however, that by doing this we are inventing what it means to "round down." In common language, you generally can't & # 39; round & # 39; without reference to something: & # 39; rounds to the nearest whole number & # 39; or & # 39; rounds to the nearest ten & # 39; or something like that. Used alone, the phrase is not clear: it could mean & # 39; to the nearest whole number & # 39; or & # 39; to the nearest integer & # 39; or & # 39; to the nearest non-fraction & # 39 ;, and not all of these are meanings that result in a reasonable game (although all, except & # 39; not fraction & # 39; because that is an incoherent idea in its expression usual, means 3/2 rounds to 1). Since rounding to the nearest whole number is the least terrible rule in general, when this rounding rule is used, it must be assumed that it does.

Group theory gr: how do reflection groups relate to general point groups?

I always tried to understand how finite reflection groups from $ Bbb R ^ d $ (of some fixed dimension $ d $) relate to the point groups of the same space $ smash { Bbb R ^ d} $ (finite subgroup of the orthogonal group $ smash { mathrm O ( Bbb R ^ d)} $)

Initially, I had the impression that each group of points is a subgroup of a finite reflection group. This turned out to be incorrect, which is obvious in retrospect. Many reflection groups have symmetries in the placement of their mirrors that can be used to enlarge the group.

So let's take these expanded groups instead. From my geometric understanding, by that I mean the symmetry groups of the uniform polytopes. Then i will call you uniform dot groups. Most (or all?) Of uniform polytopes can be generated from a reflection group, and then have all the symmetries of this group, but could have more.

Question: Is each group of points a subgroup of a uniform group of points?

With regard to the answer to that question, I am open to any statement that sheds light on the location of reflection groups (or groups easily derived from them) within the family of general point groups.

mysql – Group the results of two different tables at the same times

I have two simple tables:

inside

id | timestamp | temp | humi

outdoor

id | timestamp | temp

and two selections that give me time and average temperature grouped by the same hour during the last 24 hours:

SELECT DATE_FORMAT(timestamp, '%H:00') AS time, round(avg(temp), 1) as avg_out_temp
FROM outdoor
WHERE timestamp >= now() - INTERVAL 1 DAY
GROUP BY DATE_FORMAT(timestamp, '%Y-%m-%d %H')
ORDER BY timestamp ASC;

SELECT DATE_FORMAT(timestamp, '%H:00') AS time, round(avg(temp), 1) as avg_in_temp
FROM indoor
WHERE timestamp >= now() - INTERVAL 1 DAY
GROUP BY DATE_FORMAT(timestamp, '%Y-%m-%d %H')
ORDER BY timestamp ASC;

and now what I have to do is group those two results at the same time, with respect to the possibility that there can be no records in inside or outdoor table all the time, so I need to get:

time | avg_out_temp | avg_in_temp
11:00 | 12.5 | 21.4
12:00 | 13.9 | null
13:00 | null | 22.4
14:00 | 14.0 | 22.5