## customs and immigration – Petition for Adjustment of Status while extension of stay is still pending?

An elderly couple came to the US to visit their daughter on a visitor’s visa toward the end of last year. Due to the coronavirus outbreak, they applied to extend their stay by six months. Application was received but the outcome still pending. Since the COVID situation has not blown over and they do not feel it is safe to travel for who knows how long, their daughter (a US Citizen) wants to petition to adjust their status with forms I-130 and I-485. The question is, can she do this now, while the original extension of stay is still pending?

## reference request – Does a generalization of Tietze’s extension theorem hold for set-valued functions?

Let $$X$$ be a normal topological space. Tietze’s extension theorem says that if $$A subset X$$ is closed, then a continuous function $$f: A to mathbb R^n$$ can be extended to a continuous function whose domain is all of $$X$$. The theorem generalizes to functions taking values in any locally convex linear space (see this).

I am wondering if the theorem holds for certain set-valued functions.

In particular, let $$phi$$ be a function from closed $$A subset X$$ into compact subsets of $$mathbb R^n$$. To say that $$phi$$ is continuous on $$A$$ means that the following conditions are met for every $$x in A$$:

(1) For every neighborhood $$U$$ of $$phi(x)$$, there is a neighborhood $$V$$ of $$x$$ such that $$phi(y) subset U$$ for all $$y in V$$;

(2) For every open subset $$U$$ of $$A$$ for which $$phi(x) cap U neq emptyset$$, there is a neighborhood of $$V$$ of $$x$$ such that $$phi(y) cap U neq emptyset$$ for all $$y in V$$.

Can $$phi$$ be extended to a continuous set-valued function whose domain is all of $$X$$?

In principle, I don’t mind assuming that $$X$$ is actually a subset of $$mathbb R^m$$.

## magento2 – Magento 2 how add extension attribute to order item

I need to save the extension attribute for Order item. I have tried using plugin with below code, but it is not working for me. I have placed a log inside the method but the method is not working.

``````<type name="MagentoSalesApiOrderItemRepositoryInterface">
<plugin name="order_item_extension_attr" type="VendorCustomModulePluginModelTest"/>
</type>

public function afterGet(
MagentoSalesApiOrderItemRepositoryInterface \$orderItem,
MagentoSalesApiDataOrderItemExtensionInterface \$extension = null
) {

}
``````

How to save and get order item extension attribute?

## how could i add shipping and invoicing feature to manthan multiseller extension

i am new in magento using magento 1.9.3 version for my magento store added manthan multi seller extension to make store multi seller platform but extension does not provide invoicing and shipping features to vendor .how could i integrate shipping and invoice generation in vendor using manthan multi seller extension.Can anyone help me?

## magento2 – When I upload my extension in magento marketplace it show “Failed to open file composer.json. Please verify the archive”

{
“name”: “webgensis/module-faq”,
“description”: “Magento2 FAQ Module”,
“type”: “magento2-module”,
“version”: “2.0.1”,
“authors”: [
{
“name”: “Webgensis”,
“email”: “mail.info@webgensis.com”
}
],
“support”: {
“issues”: “https://webgensis.com/”
},
“files”: [
“registration.php”
],
“psr-4”: {
“WebgensisFaq”: “”
}
}
}

I’ve created a chrome extension and published it on the Chrome Web Store. So I’m able to modify/update it in the Developer Dashboard but how can I give the access to it to another developer so that he can also make some modification?

## Visa extension due to COVID-19

My brother in law arrived in the USA as la tourist and his visa expires in mid August. Currently the Trinidad airport remains closed with no opening dates set

Does he fall under any exemption or does he still have to file for an extension. If so does he have to pay the ree

## Chrome extension for FE Web Devs to mock APIs

Inspired by Postman, my team decided to develop MockMan – a Chrome extension that allows you to easily mock API requests, so that FE developers can build end-to-end UI experiences, without waiting for BE APIs.

Posting to promote a chrome extension that we built to help frontend engineers —

It provides mock api responses for AJAX requests. (Postman for Frontend)

This is essentially built to increase productivity in frontend development. Made for developers, it lets users to define requests (url, method and mock response) for AJAX calls. Response can be a JSON object or an error. It includes JSON formatter, and JSON viewer to better visualize data in collapsible form.

The JSON object maker lets users to make the object in JS syntax and the formatter will convert it into valid JSON object with inverted commas and no trailing commas etc. Steps for Users – 1. Define the api url, method, response JSON or error msg to be mocked. 2. Refresh the project and the ajax request will be mocked. Mocked url will disappear from network tab and appear in console.

## How can frontend developers create mock APIs using a Chrome Extension?

Inspired by Postman, my team decided to develop MockMan – a Chrome extension that allows you to easily mock API requests, so that FE developers can build end-to-end UI experiences, without waiting for BE APIs.

Posting to promote a chrome extension that we built to help frontend engineers —

It provides mock api responses for AJAX requests. (Postman for Frontend)

This is essentially built to increase productivity in frontend development. Made for developers, it lets users to define requests (url, method and mock response) for AJAX calls. Response can be a JSON object or an error. It includes JSON formatter, and JSON viewer to better visualize data in collapsible form.

The JSON object maker lets users to make the object in JS syntax and the formatter will convert it into valid JSON object with inverted commas and no trailing commas etc. Steps for Users – 1. Define the api url, method, response JSON or error msg to be mocked. 2. Refresh the project and the ajax request will be mocked. Mocked url will disappear from network tab and appear in console.

## abstract algebra – proof verification: algebraic extension (of F) containing all zeros of F[x] is algebraically closed.

This is Exercise 32.34 in Fraleigh’s book, ‘A first course in abstract algebra’.

Show that if $$E$$ is an algebraic extension of a field $$F$$ and contains all zeros of every $$f(x) in F(x)$$, then $$E$$ is algebraically closed field.

Below is my proof which I want to get verified. I’m quite certain with my proof, but since this is the first time for me to study algebra, it feels like I’m missing something.

Suppose that there exist polynomial $$g(x) in E(x)$$ which has no zero in $$E$$. Then by Kronecker’s Theorem, there exists field $$K$$ such that $$E le K$$ and $$K$$ contains zero of $$g$$, which I will denote by $$alpha$$. Then we have $$F le E le E(alpha) le K$$, since $$E(alpha)$$ is the smallest field which contains both $$E$$ and $$alpha$$. Since $$E$$ is an algebraic extension of $$F$$ (by assumption) and $$E(alpha)$$ is an algebraic extension of $$E$$ (because $$g(alpha)=0$$), $$E(alpha)$$ is an algebraic extension of $$F$$. Thus, $$alpha$$ is a zero of polynomial in $$F(x)$$. By assumption in question, we obtain $$alpha in E$$, a contradiction.