IBM db2 FOR XML equivalent

I have been trying to query an item with its secondary list at one time and one way is to use it for xml and subquery. I have been using this strategy with the SQL server and it works fine.

The relationship is order and order items.

for the sql server, the query might look like this:

Select O.OrderId, O.ShippingDate,
(
SELECT OI.ProductId, OI.Description, OI.Cost
OF OrderItems OI
WHERE O.OrderId = OI.OrderId
FOR XML PATH (& # 39; OrderItem & # 39;), ROOT (& # 39; OrderItems & # 39;)
) as order items
OF OR Orders 

I just need the list of items in the order to be xml, the details of the order are fine as they are.

Google's ways to apply the xml result in ibm db2, I found in your documentation on your website:
https://www.ibm.com/support/knowledgecenter/en/SSEPGG_9.7.0/com.ibm.db2.luw.xml.doc/doc/c0052638.html

I found a piece of code:

                SELECT XMLELEMENT (NAME "saleProducts",
XMLAGG (XMLELEMENT (NAME "prod",
XMLATTRIBUTES (p.Pid AS "id"),
XMLFOREST (p.name as "name",
i.quantity as "numInStock"))))
FROM THE PRODUCT p, INVENTORY iWHERE p.Pid = i.Pid

that I applied as

SELECT O.OrderId, O.ShippingDate,
XMLELEMENT (NAME "Order items",
XMLAGG (XMLELEMENT (NAME "Order item",
XMLATTRIBUTES (OI.ProductId AS "ProductId"),
XMLFOREST (OI. Description as "Description",
OI. Cost as "Cost"))))
Of Orders O, OrderItems OI
WHERE O.OrderId = OI.OrderId 

But in the run, IBM db gives an error message:

The OLE DB provider "IBMDA400" for the linked server "XXX" returned the message "SQL0104: The token" OrderItems "was not valid. Valid Tokens 🙂 ,.
Why . . . . . : A syntax error was detected in the "OrderItems" token. The "OrderItems" token is not a valid token. A partial list of valid tokens is) ,.
This list assumes that the statement is correct until the token.
The error may be earlier in the declaration, but the syntax of the declaration seems to be valid until this moment. Recovery . . :
Do one or more of the following actions and try the request again:
Verify the SQL statement in the "OrderItems" token area. Correct the statement.
The error could be a missing comma or quote, it could be a misspelled word or it could be related to the order of the clauses.
If the error token is, correct the SQL statement because it does not end with a valid clause. "

Help

Checking if large lists are equivalent does not work

So I'm working with large lists (more than 500 elements), let's call them list1 Y list2. I have edited the list1 Y list2 So that both do not contain repeated elements. I have tried the commands

list1 == list2

Y

Order[list1]== Order[list2]

to check if both lists are the same, but instead of getting a true or false output, I get an exit from the statement, except that list1 Y list2 They are replaced with the physical lists themselves. For example, if I define

list1: = {1,2,3}
list2: = {2,3,4}

so

list1 == list2

To return to

{1,2,3} == {2,3,4}

instead of false. What am I doing wrong and how can I solve this? I would be surprised if this evaluation only worked for lists small enough …

Equivalent of IMPORTRANGE () with script in Google Sheets

Since Importrange () does not work as expected, do you know how you could express, for example, the following function with a script?

= {IMPORTRANGE ("SheetKey", "SheetName1! A: J"); IMPORTRANGE ("SheetKey", "SheetName2! A2: J"); IMPORTRANGE ("SheetKey", "SheetName3! A2: J")}

Thank you

Measurable sets – Measurement of equivalent definition (carateodoria)

How to prove the following?
Yes $ E subset mathbb {R} ^ d $ measurable, that is $ forall epsilon, exists O supset E $ open set such that $ m ^ { ast} (O setminus E) leq epsilon $ then (measurable carateodoria) for all $ A $ set, $ m ^ { ast} (A) = m ^ { ast} (A cap E) + m ^ { ast} (A setminus E) $?

What would be the most purely functional equivalent to the generators?

Some programming languages, aside from the functions, have generators (for example, the performance of Python). Although the generators are introduced in this Python tutorial on functional programming, I do not think they can be considered functional programming, because they have status and vary implicitly.

Generators remember laziness in purely functional languages ​​such as Haskell. Apart from laziness, are there other purely functional alternatives to have a construction similar to generators? Do you have an example?

Theory of numbers: what is the equivalent of the integers symbol Z for n only integer bits?

We refer to the set of all integers as $ mathbb {Z} $. Now suppose we have a set of integers that can be kept within a computer variable of $ n $ bit width Clearly they can only be of $ 2 ^ {n} $ Scope, signed or not. How would we symbolize that? Is there something that is done to the zed, or is it simply left? $ mathbb {Z} $?

Gummies Cbd that can also have an equivalent effect.


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logic: are the two properties LTL $ GF ( psi_1 land F psi_2) $ and $ GF ( psi_2 land F psi_1) $ equivalent?

Is $ GF ( psi_1 land F psi_2) $ equivalent to property $ GF ( psi_2 land F psi_1) $?

Tried:

In the first property each state must see eventually $ psi_1 $ Y $ psi_2 $, in the second property also each state must see $ psi_1 $ Y $ psi_2 $As such, the two properties must be equivalent. Is this correct?

Amazon Web Services: What is the equivalent of GCP to AWS Cognito's authenticated user roles?

I am migrating an AWS application, where Cognito UserPools is using to grant an authenticated user a limited read and write access to the records that match the UID. I'm aware that Firebase enables user authentication, but what happens then (assuming I want to use more than the Firebase DBs)? Can I use a GCP service account to perform operations on the Cloud DataStore in the same way? It seems that I do not see as much documentation on this approach for Google compared to the full documentation available for AWS.

Function construction: how to perform conv2 convolution equivalent of two vectors in Mathematica?

I have a matlab code

filter = 1;
F = conv2 (double ([1 2 1]),double([1 2 1]& # 39;)) / sixteen;
for i = 1: some_integer
filter = conv2 (double (filter), double (F));
end`

In the code F = conv2 (double ([1 2 1]),double([1 2 1]& # 39;)) / sixteen; is equal to
a 3 x 3 matrix {{0.0625, 0.125, 0.0625}, {0.125, 0.25, 0.125}, {0.0625, 0.125, 0.0625}}

the filter changes the value in the first iteration of 1 to F and then in successive iteration the result (convolution matrix) becomes larger and larger.

I am having problems making this Convolution in Mathematica despite having consulted the documentation. Any idea how such a convolution could be made?

my attempt then to calculate F before the loop looks wrong in some way.

F = Flat[(ListConvolve[{{0, 0, 0}, {1, 2, 1}, {0, 0, 0}}, {{1, 2, 1}, {1, 2, 1}, {1, 2, 1}}, {-1, 1}, g, Plus, List]/16.0), 2]