Tag: double

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architecture: how to design / design a double navigation bar interface using Native JS

A design pattern that I admired is a double navigation bar on the left side. When you click on a button on the left, it has two functions. The first is that it controls the second section of the navigation bar that, when clicked, alternates the new content that can act as a further navigation to show content. The second function performed by the first navigation bar is that it loads a new complete route that is only loaded in a section as an iframe area.

How could you / the best solution to design this when, when you click on a button in the navigation bar that loads a new route, the second navigation bar remains in what is loaded and does not load to the state of a bar default navigation, which would happen whenever a new route was created? loaded.

Then, if I had to click on an option that changes the 2nd navigation bar and then click on a new route, I would only change to the new route and it would not affect the 2nd navigation bar.

Double navigation bar

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visas: double citizen of the VWP countries and possible re-entry to the United States in the other

I know, but out of curiosity, someone can leave the US UU With the passport that you entered with your visa exemption (before 90 days), immediately reapply for your other country passport (eligible) and re-enter with a new 90 days?

Or will everything be linked electronically and will they call you to the border?

Thank you!

Unicode analysis with keys without double quotes in Python

I'm trying to convert the Python Unicode object below without double quotes to json.

x = {
version: & # 39; 2.1.2 & # 39 ;,
dipa: & # 39; 1.2.3.4 & # 39 ;,
dipaType: & # 39; & # 39 ;,
Customer information: [{
            name: 'xyz',
            id: 1234,
            account_id: 'abc',
            contract_id: 'abc',
            in_use: true,
            region: 'NA',
            location: 'USA'
        },
        {
            name: 'XYZ',
            id: 9644,
            account_id: 'qwerty5',
            contract_id: 'qscdfgr',
            in_use: true,
            region: 'NA',
            location: 'cambridge'
        }
    ],
maxAlertCount: 2304,
ongress: false,
ScrubCenters: [{
        name: 'TO',
        percentage: 95.01,
        onEgress: false
    }],
status: & # 39; update & # 39 ;,
updated: & # 39; 1557950465 & # 39 ;,
vectors: [{
            name: 'rate',
            alertNames: ['rate'],
ongress: false,
Alerts: [{
                key: '1.2.3.4',
                source: 'eve',
                eNew: '1557943443',
                dc: 'TOP2',
                bond: 'Border',
                percentage: 95.01,
                gress: 'ingress',
                sourceEpochs: ['1557950408',
                    '1557950411',
                    '1557950414',
                    '1557950417',
                    '1557950420',
                    '1557950423',
                    '1557950426',
                    '1557950429',
                    '1557950432',
                    '1557950435',
                    '1557950438',
                    '1557950441',
                    '1557950444',
                    '1557950447',
                    '1557950450',
                    '1557950453',
                    '1557950456',
                    '1557950459',
                    '1557950462',
                    '1557950465'
                ],
name: & # 39; tariff & # 39 ;,
category: & # 39; tariff & # 39 ;,
level: & # 39; alarm & # 39 ;,
Data type: & # 39; value & # 39 ;,
data: 19.99,
time stamp: 1557950466,
type: & # 39; alert & # 39 ;,
Value: 95.01,
updated: & # 39; 1557950465 & # 39;
}],
dcs: ['TO'],
captivity: ['Bo']
        }
{
name: & udp & # 39; udp & # 39 ;,
alertNames: ['udp'],
ongress: false,
Alerts: [{
                key: '1.2.3.4',
                source: 'top',
                eNew: '1557943500',
                dc: 'TO',
                bond: 'Bo',
                percentage: 95.01,
                gress: 'ingress',
                sourceEpochs: ['1557950408',
                    '1557950411',
                    '1557950414',
                    '1557950417',
                    '1557950420',
                    '1557950423',
                    '1557950426',
                    '1557950429',
                    '1557950432',
                    '1557950435',
                    '1557950438',
                    '1557950441',
                    '1557950444',
                    '1557950447',
                    '1557950450',
                    '1557950453',
                    '1557950456',
                    '1557950459',
                    '1557950462',
                    '1557950465'
                ],
name: & udp & # 39; udp & # 39 ;,
category: & # 39; udp & # 39 ;,
level: & # 39; alert & # 39 ;,
data_type: & # 39; named_values_list & # 39 ;,
data: [{
                    name: 'Dst',
                    value: 25
                }],
time stamp: 1557950466,
type: & # 39; alert & # 39 ;,
updated: & # 39; 1557950465 & # 39;
}],
dcs: ['TO'],
captivity: ['Bo']
        }
{
name: & # 39; tcp & # 39 ;,
alertNames: ['tcp_condition'],
ongress: false,
Alerts: [{
                key: '1.2.3.4',
                source: 'to',
                eNew: '1557950354',
                dc: 'TO',
                bond: 'Bo',
                percentage: 95.01,
                gress: 'ingress',
                sourceEpochs: ['1557950360',
                    '1557950363',
                    '1557950366',
                    '1557950372',
                    '1557950384',
                    '1557950387',
                    '1557950396',
                    '1557950399',
                    '1557950411',
                    '1557950417',
                    '1557950423',
                    '1557950426',
                    '1557950432',
                    '1557950441',
                    '1557950444',
                    '1557950447',
                    '1557950450',
                    '1557950456',
                    '1557950459',
                    '1557950465'
                ],
name: & # 39; tcp & # 39 ;,
category: & # 39; tcp & # 39 ;,
level: & # 39; alert & # 39 ;,
Data type: & # 39; named & # 39 ;,
data: [{
                    name: 'TCP',
                    value: 25
                }],
time stamp: 1557950466,
type: & # 39; alert & # 39 ;,
updated: & # 39; 1557950465 & # 39;
}],
dcs: ['TO'],
captivity: ['Bo']
        }
],
Timestamps: {
FirstAlerted: & # 39; 1557943443 & # 39 ;,
lastAlerted: & # 39; 1557950465 & # 39 ;,
lastLeaked: null
}
}

I tried using hjson and demjson

Import Hjson
result = hjson.loads (x)

import demjson
result = demjson.loads (x)

Current result:

hjson.scanner.HjsonDecodeError: Additional data: line 156 column 1 – line 620 column 27 (char 4551 – 232056)

demjson.JSONDecodeError: unexpected text after the end of the JSON value

Expected result:

Json object

doublespend – How does the double expense of bitcoin affect the omni sets?

I have a question about omni layer and bitcoin double-gas. I would be very grateful if someone answered.

Suppose I made a transaction tx_1 in the bitcoin network from the X address to the Y address and one of the outputs and its amount (546 satoshi) of bitcoin were linked to the amount of N of the omni asset (for example, Tether). So I simply sent ownership of omni asset from the X address to the Y address. Then I bounced this amount of N with another amount of satoshi, which I had had before sending Omni tied with 546 satoshi in tx_1 to this address. And then I sent this amount of omni asset to another address Z doing transaction tx_2. Then, for some reason, transaction tx_1 was canceled (double expense). And I have a question in this case omni assets will belong to the address Z or X?

nt.number theory – Double Cosets and Weber's function

Leave $ n $ be an odd positive integer leave $ mathcal M_n $ is the set of all $ 2 $-by-$ 2 $ Primitive matrices with integral entries and with determinant. $ n $.

Leave $ Gamma $ be the subgroup of $ operatorname {SL} _2 ( mathbb Z) $ generated by the matrices $ T ^ 2 = begin {pmatrix} 1 & 2 \ 0 & 1 end {pmatrix} $ Y $ S = begin {pmatrix} 0 & -1 \ 1 & 0 end {pmatrix} $.

So
$$ Gamma = bigg lbrace begin {pmatrix} a & b \ c & d end {pmatrix}: begin {pmatrix} a & b \ c & d end {pmatrix} equiv begin {pmatrix} 1 & 0 \ 0 & 1 end {pmatrix} text {or} begin {pmatrix} a & b \ c & d end {pmatrix} equiv begin pmatrix} 0 & 1 1 & 0 end {pmatrix} text {mod} 2 bigg rbrace. $$

How many cosets are there in $ Gamma backslash mathcal M_n / Gamma $ ?

Leave $ r, s, t $ be positive integers suppose that $ rt = n $, $ s <2t $, cast $ s $ even. There are matrices $ A, B in Gamma $ such that $ A begin {pmatrix} n & 0 \ 0 & 1 end {pmatrix} B = begin {pmatrix} r & s \ 0 & t end {pmatrix} $?

Motivation.

The Hauptmodul for the group. $ Gamma $ is the function
$$ mathfrak f ( tau) ^ {24} = q ^ {- 1/2} prod_ {k = 1} ^ { infty} (1 + q ^ {n-1/2}). $$
Leave $ Phi_n (X) $ be the minimum polynomial of $ mathfrak f (n tau) $ 24 finished $ mathbb C ( mathfrak f ^ {24}) $. Is $ mathfrak f left ( frac {r tau + s} {t} right) $ a root of $ Phi_n (X) $?

procedures: double citizenship with the US UU and Australia, but with only a US passport. UU

Probably not. As Australian citizens, their children are not eligible to receive ETA, and they will not be allowed to travel on the plane without one. If you arrive at the border with Australia, there may be some problems while things are resolved, and more problems if you leave the country without an Australian passport (although you can request one while you are in the country to avoid this).

Having said that, some people have reported that they request ETA as Americans and that (incorrectly) they have been granted one anyway, so their mileage may vary.

Differential geometry – Double frame in Riemannian metrics.

Suppose we have a Riemannian metric. $ ds ^ 2 = Edu ^ 2 + 2Fdudv + Gdv ^ 2 $ in a coordinated local neighborhood $ (U; (u, v)) $ Prove that for the following vector fields:

$$ e_ {1} = frac {1} { sqrt {E}} frac { partial} { partial u}, e_ {2} = frac {-1} { sqrt {EG- F ^ 2}} left ( frac {F} { sqrt {E}} frac { partial} { partial} – sqrt {E} frac { partial} { partial v} right ) $$

the $ 1- $shapes:
$$ omega_1 = sqrt {E} left (du + frac {F} {E} dv right), omega_2 = sqrt { frac {EG-F ^ 2} {E}} dv $ PS
satisfy
$$ omega_i (e_k) = delta_ {ik} $$

My work: Let $ p (u, v) $ A differentiable function, I believe that I must show fervently that $ omega_1 (e_1 (p)) = p $, that is to say $ omega_1 (e_1) = 1 $ The identity function.

$$ omega_1 left ( tfrac {1} { sqrt {E}} tfrac { partial} { partial u} (p) right) = tfrac {1} { sqrt {E}} tfrac { partial} { partial u} ( omega_1 (p)) $$
I do this because a $ 1-form $ $ alpha $ It is such that $ alpha (fX) = f alpha (X) $. Then it is correct that
$ omega_1 (p) = sqrt {E} left (pdu + frac {F} {E} pdv right)? $
and then apply the partial derivative, my problem is that I do not know how to operate the $ 1 $-to form. Anyone can guide me on how I can achieve the result or an explicit way to operate $ omega_1 $ Y $ omega_2 $?

I am using the book "Umehara, differential geometry of surfaces".

Failed to deallocate Matrix – double free or corruption C

Hi, I'm having a problem trying to free in an assigned array, I'm doing a program to rotate an array, after assigning I execute a function and then the free does not work, returning the double free error or corruption

cop = malloc (x * sizeof (long int *));
(int k = 0, k <x, k ++)
{
cop[k] = malloc (and * sizeof (long int *));
}

transfected (mat, COP, Lin, et al, theta variables);

(int i = 0; i <x; i ++)
{
free (COP[i]);
}
free (COP);

The function used is the following: 

empty transferase (long mat ** int, long int ** policeman, long lin int, long, int col, Int theta much, much int var)
{
long int value;
// x * sin (theta * PI / 180) + and * cos (theta * PI / 180);
// x * cos (theta * PI / 180) - and * sin (theta * PI / 180);
(int i = 0; i <lin; i ++)
{
(int k = 0; k) < col; k++)
        {
            long int a = k*cos(theta*PI/180) - i*sin(theta*PI/180);
            long int b = k*sin(theta*PI/180) + i*cos(theta*PI/180);
            a += var;
            cop[b][a] = mat[i][k];
            if (a > 0)
{
cop[b][a-1]    = mat[i][k];
}
}
}
}

This function relates the lin / col of one matrix and rotates to b / a of another (in the case, the matrix cop), x and y is the size of the matrix necessary for the image to be broken.
Theta = 90º as an example