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Bandwidth cost : Colocation vs Rental Dedi

Hello,

Can someone explain why bandwidth cost is too high with colocation than rental dedicated?

Like rental server with 50tb or 100tb ban… | Read the rest of https://www.webhostingtalk.com/showthread.php?t=1839448&goto=newpost

mathematical optimization – Is there a better way to simulate quadratic cost MPC problems?

I would like to know if there is a more straightforward or a better way in terms of code length and accuracy to simulate MPC (or essentially optimal control) problems as compared to what I am doing.

The receding horizon optimal control problem I want to simulate is as follows:
$$
begin{equation}
begin{aligned}
min_{{u_0, …,u_{N-1}}} ; & sum_{p=0}^{N-1} x_p^TPx_p + x_N^TQx_N \ text{subject to}
;& x_{k+1}=Ax_k+Bu_k,; ; k = 0, 1,…,N-1 \& A_x x_k leq b_x, ;; x_k in mathbb{R}^n, ;; k = 0, 1…,N-1 \ & A_u u_k leq b_u, ;; u_k in mathbb{R}^m, ;; k = 0, 1…,N-1 \ & A_N x_N leq b_N, ;; x_N in mathbb{R}^n\ &
x_0=x(0)
end{aligned}
end{equation}
$$

What I have done is translate the above problem into a form which I can give to Mathematica’s QuadraticOptimization solver. Going as per Sec. 11.3.1 of Predictive Control for linear and hybrid systems (this book is available for free on author’s website and this is not an illegitimate copy), the problem can be re-cast as below:
$$
begin{equation}
begin{aligned}
min_{V_0} ; & V_0^TMV_0 \ text{subject to}
;& J_0V_0 leq w_0 \& begin{bmatrix} 0 & … & 0 & 1 & … & 1 end{bmatrix}V_0=x(0)
end{aligned}
end{equation}
$$

where $V_0={u_0,…,u_{N-1},x(0)}$ and the row matrix in second constraint has $mN$ zeros and $n$ ones, which basically means that the last $n$ components of $V_0$ make up the vector $x(0)$.

Is there a more straightforward way?

A bit of a background

This works but I don’t know if it gives correct results. I tried comparing my MPC results with a few examples from research papers and lecture notes and the outcome was a mixed bag. For some, results matched perfectly, for some results matched for certain time periods only and for some it threw the error of no points satisfies the constraints. It is of course an issue for a separate question on MathematicaSE but this is what prompted me to ask this question.

Thank you for your help!

dnd 5e – Variant rule: how can we lighten the cost of chugging potions in battle?

So, we know how this works: potions are listed as magic items in the DMG, and to use a magic item, one must use activate magic item, which costs one action and, to the best of my knowledge, there’s no way to relieve such cost (a thief’s fast hands don’t apply since, again, this is a magic object and for some reason it’s wholly different).

Now, I’m sure most of us can relate to this this situation” you find yourself in the midst of a bloody battle, half-dead and surrounded by enemies, when a hope shines through the perils: your bag full of refreshing healing potions, which beg to be savored by your dusty lips. You extend your empty hand (or drop whatever you were holding since only one free interaction is allowed per turn and tidily stowing your sword consumes it… the ancients would say junky lex, sed lex), grab a delicious 4d4+4 health potion and prepare to consume your action in the process… “But wait” I hear you say, “Doesn’t it heal an average of 14Hp?” Indeed. “And don’t my enemies dish out an average of -whatever number higher or equal to 14-“? Right on the money. “So I can’t move or I’ll trigger free opportunity attacks – and the hostile creatures will still be able to reach me (if they have at least my speed) – but I can’t disengage or do any evasive meneuvers or I won’t be able to drink… So I can only chug and deplete my precious potions while they gank on me till they’ll inevitably reduce me to a pulp?” Bingo.

Healing potions are scarcely useful in battle, even compared to healing spells: despite being limited -to the number of spell slots left-, they also offer several ductile options: most are available from level 1 (healing word, cure wounds) and therefore ever more plentiful, they can be upcast (while one cannot chug more than one potion per turn), some cost a bonus action (healing word), and the strongest have an AoE healing (mass cure wounds*). The scale is so tipped in favor of spellcasters that even in campaigns with regular supplies of cheap, high level potions, they rarely compare to the dreaded healbot.
How can we houserule more versatility and usefulness out of potions and rely less, possibly not at all, on healers?

Most common solutions I found were:

  1. Drink healing potions as a bonus actions, which definitely helps and resembles healing word, but, seems e bit too much and inconsistent (I mean, what about other potions?);
  2. Dodge&drink, a solution Hipsters&Dragons came up with, which lets you take the dodge action freely when you drink a potion (https://www.hipstersanddragons.com/drinking-a-healing-potion-in-combat/), which is neat, but won’t save you from any save-throw imposing fireball;
  3. If you retrieve a healing potion this turn and drink it the next one (with two separate free interactions), you don’t need to waste any action since drinking only takes a free interaction”. Crawford seemed to uphold this interpretation (https://www.sageadvice.eu/2017/01/19/the-rule-for-drinking-a-potion/), but didn’t the DMG establish that potions are magic items and you need to, somehow, activate them? Inconsistencies aside, this interpretation doesn’t really help in the heat of battle, does it?

So, what do you suggest?

usa – How to minimize cost for cash withdrawals at French ATMs with a Bank of America card?

Bank of America is part of the so called Global ATM alliance. According to Bank of America’s FAQ (see “Using your ATM card or debit card at an international ATM” and then “What is the Global ATM Alliance?):

Use your Bank of America ATM or debit card within the Global ATM Alliance to avoid the non-Bank of America usage fee for each withdrawal, transfer or balance inquiry, as well as the ATM operator access fee. An international transaction fee of 3% will apply when converting your currency.

In France, BNP Paribas is part of the alliance and you can use your Bank of America card at their ATMs to minimize your cost.

Note that BNP Paribas doesn’t charge any fees for using their ATM (according to TransferWise), so the only fee you’ll pay is the relative transaction fee. There seems to be no minimal transaction fee from Bank of America’s fee schedule (it’s hard to link to it, you have to select Bank of America Core Checking and enter a ZIP code, then go to ATM fees and View more important information), so it shouldn’t matter whether you withdraw a large amount once or many smaller amounts (but it’s better to check after your first withdrawal just to be sure).

However, when you try to withdraw money from a BNP Paribas ATM, they might offer you to do a conversion for you. In this case they will offer you two options: a.) to withdraw the Euro amount in which case the currency conversion will be handled by your bank, or b.) to withdraw a Dollar amount in which case they handle the conversion. Of course, they don’t do this for free and I’ve never been anywhere where it would have been better to use the conversion offered by the ATM. Bank of America agrees on that:

Bank of America will assess an international transaction fee of 3% of the converted US dollar amount. Foreign ATM operators may offer to do your currency conversion for you, but they may charge a higher fee for conversion. To insure that your currency conversion does not incur a fee higher than 3%, you may refuse the ATM operator’s offer to convert the amount of the transaction.

For next time though you could consider getting a bank account with debit card where you even don’t pay (or are reimbursed for) currency transactions. Such accounts are offered for example by Charles Schwab or Capital One 360.

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ASVhost has been a major presence in the Web Hosting market since 2017. All of our staff is in-house and we pride ourselves on operating our own networks and infrastructures. ASVhost is committed to providing our customers with Semi-Managed Support that is unsurpassed in the industry and that is truly available 24 hours a day, 7 days per week. 99% of the tickets we receive are answered within a 30 minute time period!

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What is cost of building small datacenter?

What can it cost in germany for example to build a mini data center with 46 or 2 x 46 Rack space?… | Read the rest of https://www.webhostingtalk.com/showthread.php?t=1838771&goto=newpost

Minimum cost bin assignment

I’ve been trying to solve the below problem the entire day but couldn’t come up with a solution. I have the suspicion that it could by solved by a graph algorithm (or maybe some greedy approach?) but couldn’t find something. Thanks for the help!

You have n baskets and m cats (m >> n). The cats don’t like each other, H_{ij} denotes how much cat i hates cat j (H_{ji} = H_{ij}). Each basket b has a capacity C_b and each cat c needs space C_c.

How can you minimize the sum over the H_{ij} of all cat pairs (i,j) that are assigned to the same basket? Every cat needs to be assigned to a basket.

crafting – What is the DC and how much does it cost to repair a Sturdy Shield?

The Repair activity says, in part –

The GM sets the DC, but it’s usually about the same DC to Repair a given item as it is to Craft it in the first place.

Crafting says –

When a character Crafts an item, use the item’s level to determine the DC, applying the adjustments from Table 10–6 for the item’s rarity if it’s not common. You might also apply the easy DC adjustment for an item the crafter has made before. Repairing an item usually uses the DC of the item’s level with no adjustments, though you might adjust the DC to be more difficult for an item of a higher level than the character can Craft.

The Level-based DC table lists the DC of 4th level as 19. This would be the default DC to repair the Sturdy Shield.

There is no cost involved to repair an item. However, you do need to have a Repair Kit available, which presumably provides any supplies required.

As listed in the Repair Activity,a success will restore 5 Hit Points to the item, plus an additional 5 per proficiency rank in Crafting (for a total of 10 HP for trained, 15 HP for expert, 20 HP for master, or 25 HP for legendary). A Critical success will double this, and a Critical Fail will cause more damage. Therefore, the number of attempts required to repair the shield will vary considerably based on the capability of the repairer. Assuming a Trained Crafter, at least 3 Successful repair attempts will be required (taking 10 minutes per attempt) to repair all 30 of the damage.

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