javascript – Apply by default a 0 on the display of my calculator

I currently have these buttons and a simple H1 to show the functionality of them.
I need to put on the screen by default a 0, and that after pressing a button this 0 is replaced by the button number that I pressed.

    class App extends React.Component {
        constructor(props) {
            super(props);
            this.state = { valueToRender: '' };
            this.renderValue = this.renderValue.bind(this);
        }

        renderValue(value) {
            this.setState({ ...this.state, renderValue: value });
        }

        render() {
            return (
                

{this.state.renderValue}

export default App;

c # – How do I code a + tax button on my calculator? I just want to add a button so when I click on it there is a tax exit

WindowsFormsApp1 namespace
{
public partial class Form1: Form
{
Double value = 0;
String operation = "";
bool operation_pressed = false;
Public form1 ()
{

        InitializeComponent();
    }



    private void button10_Click(object sender, EventArgs e)
    {

    }

    private void button9_Click(object sender, EventArgs e)
    {

    }

    private void button8_Click(object sender, EventArgs e)
    {

    }

    private void button7_Click(object sender, EventArgs e)
    {

    }

    private void button6_Click(object sender, EventArgs e)
    {

    }

    private void button5_Click(object sender, EventArgs e)
    {

    }

    private void button4_Click(object sender, EventArgs e)
    {

    }

    private void button3_Click(object sender, EventArgs e)
    {

    }

    private void button2_Click(object sender, EventArgs e)
    {

    }

    private void button1_Click(object sender, EventArgs e)
    {


    }

    private void result_TextChanged(object sender, EventArgs e)
    {

    }

    private void button13_Click(object sender, EventArgs e)
    {
        result.Text = "0";

    }

    private void operator_Click(object sender, EventArgs e)
    {
        Button b = (Button)sender;
        operation = b.Text;
        value = Double.Parse(result.Text);
        operation_pressed = true;








    }
    private void button_Click(object sender, EventArgs e)
    {

        if ((result.Text == "0") || ((operation_pressed)))
            result.Clear();
        operation_pressed = false;
        Button b = (Button)sender;



        result.Text = result.Text + b.Text;



    }                     


    private void button14_Click(object sender, EventArgs e)
    {



        switch (operation)
        {

            case "+":
                result.Text = ( value + Double.Parse(result.Text)).ToString();
                break;
            case "-":
                result.Text = ( value - Double.Parse(result.Text)).ToString();
                break;

            case "x":
                result.Text = ( value * Double.Parse(result.Text)).ToString();
                break;

            case "/":
                result.Text = (value / Double.Parse(result.Text)).ToString();
                break;


            default:
                break;





        }






        }

    private void button15_Click(object sender, EventArgs e)
    {
        result.Clear();
        value = 0;
    }

    private void TaxButton_Click(object sender, EventArgs e)
    {

    }
}

}

plugins – multi-step survey form calculator

I'm looking for a WordPress plugin where I can create a multi-step survey type form with sliders and multiple choice fields etc.

The fields will have a value for them, so when the user completes / selects in the survey, they record a numerical value that reflects the results of the users in correlation with their selected entries and add them so that you can redirect them to a page if your results meet certain range.

Anyone know of a free or paid plugin that could have this option. I really appreciate any help.

Java Kata – String Calculator

I started learning Java recently. I am currently trying to improve my spaghetti code by solving different programming puzzles.

It would be amazing if someone could give me their opinion on the string calculator that Kata specified in Coding Dojo.

Any comments to improve would be amazing …

// StringCalculator.java

public class StringCalculator {

    private float result;
    private String customDelimiter;

    private static final String DEFAULT_DELIMITER = ",";
    private static final String NEWLINE = "n";
    private static final String CUSTOM_DELIMITER_PREFIX = "/";
    private static final String CUSTOM_DELIMITER_SUFFIX = NEWLINE;

    StringCalculator() {
        result = 0;
        customDelimiter = "";
    }

    public String sum(String numbers) {
        if (numbers.isEmpty())
            return String.format("%.0f", result);

        if (isInvalidLastCharacterIn(numbers))
            return "Number expected but EOF found.";

        if (numbers.startsWith(CUSTOM_DELIMITER_PREFIX))
            numbers = setCustomDelimiter(numbers);

        if (isNewlineAtInvalidPositionIn(numbers))
            return String.format("Number expected but 'n' found at position %d.", numbers.lastIndexOf('n'));

        if (containsNegative(numbers).length() > 0)
            return String.format("Negative not allowed: %s", containsNegative(numbers));

        calculateSumOf(getStringArray(numbers));

        return hasDecimalPlaces() ? printFloat() : printInteger();
    }

    private boolean isInvalidLastCharacterIn(String numbers) {
        return Character.digit(numbers.charAt(numbers.length() - 1), 10) < 0;
    }

    private boolean isNewlineAtInvalidPositionIn(String numbers) {
        return numbers.lastIndexOf(NEWLINE) > numbers.lastIndexOf(DEFAULT_DELIMITER);
    }

    private StringBuilder containsNegative(String numbers) {
        StringBuilder negativeNumbers = new StringBuilder();

        for (String number : getStringArray(numbers))
            if (Float.valueOf(number) < 0) negativeNumbers.append(number + ",");

        boolean commaIsLastChar = negativeNumbers.length() > 0 && negativeNumbers.charAt(negativeNumbers.length() -1) == ',';

        return commaIsLastChar ? negativeNumbers.deleteCharAt(negativeNumbers.length() - 1)
                               : negativeNumbers;
    }

    private String setCustomDelimiter(String numbers) {
        int customDelimiterStart = numbers.lastIndexOf(CUSTOM_DELIMITER_PREFIX) + 1;
        int customDelimiterEnd = numbers.indexOf(CUSTOM_DELIMITER_SUFFIX);

        customDelimiter = numbers.substring(customDelimiterStart, customDelimiterEnd);

        return numbers.substring(customDelimiterEnd + 1).replace(customDelimiter, DEFAULT_DELIMITER);
    }

    private String() getStringArray(String numbers) {
        return numbers.replace(NEWLINE, DEFAULT_DELIMITER).split(DEFAULT_DELIMITER);
    }

    private void calculateSumOf(String() numbers) {
        for (String number : numbers)
            result = Float.sum(result, Float.parseFloat(number));
    }

    private boolean hasDecimalPlaces() {
        return result % 1 != 0;
    }

    private String printFloat() {
        return Float.toString((float) (Math.round(result * 100.0) / 100.0));
    }

    private String printInteger() {
        return String.valueOf((int) result);
    }
}

// StringCalculatorShould.java

import org.junit.Test;
import static org.junit.Assert.assertEquals;

public class StringCalculatorShould {
    @Test
    public void
    return_0_when_input_is_empty() {
        assertEquals("0", given(""));
    }

    @Test
    public void
    return_3_when_input_is_1_2() {
        assertEquals("3", given("1,2"));
    }

    @Test
    public void
    sum_floats_and_return_float() {
        assertEquals("6.6", given("2.2,4.4"));
    }

    @Test
    public void
    treat_newLine_as_a_delimiter() {
        assertEquals("6", given("1n2,3"));
    }

    @Test
    public void
    return_error_msg_when_newLine_at_invalid_position() {
        assertEquals("Number expected but 'n' found at position 6.", given("1,2,5,n3"));
    }

    @Test
    public void
    return_error_msg_when_delimiter_at_last_position() {
        assertEquals("Number expected but EOF found.", given("2,3,4.2,"));
    }

    @Test
    public void
    return_correct_sum_when_custom_delimiter_is_used() {
        assertEquals("3", given("//;n1;2"));
        assertEquals("3", given("//|n1|2"));
        assertEquals("8", given("//@@n1@@2@@5"));
        assertEquals("5", given("//sepn2sep3"));
    }

    @Test
    public void
    return_string_of_negative_numbers_when_negative_numbers_are_used_as_input() {
        assertEquals("Negative not allowed: -1", given("-1,2"));
        assertEquals("Negative not allowed: -4,-5", given("2,-4,-5"));
    }

    private String given(String number) {
        StringCalculator stringCalculator = new StringCalculator();
        return stringCalculator.sum(number);
    }
}

Here is a good AdSense calculator if you ever need it.

Advertising

Dont do it?

Advertise virtually anything here, with CPM banner ads, CPM email ads and CPC contextual links. You can segment relevant areas of the site and show ads based on the user's geographic location if desired.

It starts at just $ 1 per CPM or $ 0.10 per CPC.

Strange characters in the UBUNTU 18.04 calculator

Strange images in the calculator

I think the problem is related in some way to GTK, any ideas?

Javascript invoice calculator: you need help refactoring the code

I am trying to learn Javascript and I have set up an invoice calculator. Most of the lines in the code are for rounding. It has four main components:

  1. Allows you to enter the invoice amount and tip percentage
  2. Calculate the total bill divided by the number of guests
  3. Calculate the total tip
  4. Divide the invoice by number or guests

    billAmount = 134.93
    const enterTipPercent = 10
    const guests = ("Person1", "Person2", "Person3", "Person4")
    const noOfGuests = guests.length;
    console.log('Chosen tip: ' + enterTipPercent + '%')
    
    function splitBill() {
      var split = billAmount / noOfGuests; 
      var rounding = split.toFixed(2);
      var elseIf = rounding * noOfGuests;
    
    if (rounding == billAmount/noOfGuests) {
      console.log('Each person must pay: £' + rounding +' with no remainder');
    
    }
    
    else if (elseIf * noOfGuests > billAmount){
      var roundDown = Math.floor(split*100) /100;
      var remainingAmount = billAmount-roundDown*noOfGuests;
      var roundedRemainder = remainingAmount.toFixed(2);
      console.log('Each person must pay: £' + roundDown +' with £' + roundedRemainder + ' remaining');
      }
    }
    
    function calculateTip() {
      var tip = billAmount/100*enterTipPercent;
      var tipRound = tip.toFixed(2);
      return tipRound;
    }
    
    function splitTip() {
    
      if (calculateTip() * 10 == billAmount) {
        var tipShare = calculateTip();
        var tipDivide = tipShare/noOfGuests;
        var tipRound = tipDivide.toFixed(2);
        console.log('Each person must tip: £' + tipRound);
    }
      else  {
      var tipShare = calculateTip();
      var tipDivide = tipShare/noOfGuests;
      var tipRound = Math.floor(tipDivide *100) /100;
      var tipremainder = calculateTip()-tipRound*noOfGuests;
      var tipRoundRemainder = tipremainder.toFixed(2);
      console.log('Each person must tip: £' + tipRound + ' with £' + tipRoundRemainder + ' remaining');
      }
    }
    
    splitBill();
    console.log('total tip £' + calculateTip());
    splitTip();const 
    

The code I've written works fine, but I'm sure this is not the best or most efficient way I could have done it. Does anyone have any advice on how I can improve?

Hashpower: what is the algorithm to create a Bitcoin mining calculator?

I want to give an extended answer since I found the preexisting here or elsewhere that needs a little more clarification, specifically for newcomers.

Formula

To calculate the approximate total value of bitcoin earnings per month from a mining operation (regardless of mining costs (electricity, hardware maintenance, etc.)), the following formula can be used:

H = Hashrate (hashes / second)
D = Difficulty (Reference for values below)
B = Reward per Block (Reference for value below)
N = Number of days per month (default = 30)
S = Number of seconds per day (S = 60 * 60 * 24 = 86400)

Mining Profit Formula

Example

H = 21,990,232,555,520 h/s (~= 20TH/s)
D = 47,427,554,950.648
B = 25
N = 30
S = 86400

Mining Profit Formula

The total number of bitcoins won per month according to the variables defined above will be ~ 6,995. Discard N of the numerator and you will get the daily value.

Piton

A quick Python declaration as an implementation example (you can write this directly to the terminal)

$ python -c "print (30*21990232555520*25*86400)/(47427554950.648*2**32)"
$ 6.99542703277

Some references:

Difficulty (Current value | Wiki)

Block reward (Current and future values)

magento2 – Price calculator for small wine stores with multiple stores in different countries

Issue:

My friend runs some small wineries in Italy and owns 3-4 small warehouses in different European countries. He wants his online customers (wine buyers) to decide from which store they want to obtain the wine, comparing shipping prices.

If the customer is in the same country as the warehouse, it is preferable to have integration with local delivery services and online payment systems.

I am currently leaning towards Magento 2.3 + PWA Studio.

Question:

Is it possible to achieve this functionality of such a price calculator without writing a custom module?

Please check the websites worth the calculator! The | Forum Promotion

Hi,

Can you give me any comments or reviews to improve https://websitesworthcalculator.com. This is not only a tool to measure the value of websites, but allows you to view indexed pages from Google, Yahoo, Bing or the Dmoz directory, backlinks, DA, PA … In addition, you can see Information about your "Whois" domain and social network signals from your websites and more. In the result, you can see the antivirus verification through its tool. More tools are very useful to help you analyze your website.

I also hope to receive more comments from you to improve it.

Thank you