why i cant use wifi or scan for wireless networks ?

# Tag: Band

## wireless networking – Unable to print via dual band wi-fi

I used to be able to print to my HP Officejet Pro 8610 printer until I upgraded my wi-fi to using a single dual-band AC2200 Nest router. The printer is connected to wi-fi with a valid IP address (196.168.86.5). I tried removing and then reinstalling the printer to the printer list on my mac. The mac was aware of the printer (it listed the printer in the list of possible devices to add) but when I tried to add it I got the error message:

```
Unable to connect to 'HP Officeject Pro 8610 (1ED6EE)._ipp._tcp.local.' due to an error.
```

When I use the command “arp -a” from my mac I can see the printer:

```
mac-mini-2:~> arp -a
hp1ed6ee.lan (192.168.86.5) at fc:3f:db:1e:d6:f0 on en1 ifscope (ethernet)
epson5b8b9d.lan (192.168.86.36) at 0:26:ab:5b:8b:9d on en1 ifscope (ethernet)
```

I also have an Epson WorkForce 630 printer on this wi-fi network which I can print to. I am able to ping the Epson printer but not the HP printer (I get “Request timeout” messages).

I read on the internet that the problem could be that a printer using the 2.4 GHz band would not talk to a device on the 5 GHz band and indeed the HP printer is on the 2.4 GHz band and my mac is using the 5 GHz band. But the Epson printer also uses the 2.4 GHz band so that cannot be the whole story. Unfortunately, with the Nest router, it is not possible to switch my mac to using the 2.4 GHz band (at least not that I can see). I tried using a 2nd mac and had the same problem.

## real analysis – Band limited initial data : Regularity for Navier Stokes Equation defined on a Torus $mathbb{T}^m$

Consider the Navier stokes equation and the Euler equation defined on a Torus(periodic solutions).

Let the dimensionality of the space $mathbb{T}^m$ be $mge 3$.

Link to the Problem.

Has it been investigated partially or conclusively, the regularity of the solutions when the initial data $u_0(x) = u(x,0)$ is a trigonometric polynomial of a certain degree?

References to any closely related research is also appreciated.

## rom – Does LTE Band 20 (800) really matter?

I’m looking to import Redmi K30 Ultra, and since it is not available globally (only Chinese ROM), in the specs it is stated it does not support LTE B20(800). My operator provides following coverage:

4G -> B3(1800) and B20(800)

3G -> B1(2100) and B8(900)

2G -> B3(1800) and B8(900)

All other bands are supported by the mentioned device.

Now, I have some basic understanding about the topic, such as, lower frequencies means broader coverage but lower speeds and vice versa.

But I am wondering if someone could tell me will I really notice the lack of B20 (e.g. will device be prone to losing 4G connection and going to 3G often). Are there any experiences regarding this problem (not necessarily with this phone). Thanks!

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**3. What does Band Protocol offer in comparison to native blockchain-based oracle services ?Answer : **Low cost, real-time data, support for any data type, customizability, scalability and cross-chain compatibility

**4. How is the BandChain decentralized oracle network incentivized to fulfil oracle requests ?Answer : **Validators and underlying stakers receive a data request fee and block reward

**5. Why are validators who fulfil data requests on BandChain required to stake BAND ?Answer : **Align economic incentives for validators…

**6. What can BAND token holders do to help secure the network and earn a portion of data request fees ?Answer :** Delegate or stake Band for choosen validators(s).

**7. The BAND token is used to pay for transaction fees on BandChain , similarly to ETH on Ethereum. If there is a higher usage of Band oracles then … ?Answer :** More fees are generated through the network, rewarding validators ans stakers.

these answers i found it in another site . the second answer is different . can you review that and review video and tell me what is the true answer and i have question about coinbase after you review answers . thank you

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## Favorite Rock Band?

## plotting – Error band in the legend

I want to plot multiple data sets having error bands with legends **such that the style of error band is also reflected in the corresponding legend**. So for e.g. let’s say I have the following two data sets.

```
sinData = Table[{x, Around[Sin[x], 0.1*Sin[x]]}, {x, 0.1, Pi, 0.1}];
cosData = Table[{x, Around[Cos[x], 0.1*Sin[x]]}, {x, 0.1, Pi, 0.1}];
```

Now I plot them together with error bands and legend

```
ListPlot[{sinData, cosData}, IntervalMarkers -> "Bands",
IntervalMarkersStyle -> {Blue, Red}, Joined -> True,
IntervalMarkersStyle -> Gray, PlotRange -> All,
PlotLegends -> LineLegend[{"sin", "cos"}], Frame -> True]
```

Here the problem is the legends do not have the error band. So I have the following two questions based on this problem.

1] Is it possible to show the same plot with legends having a small rectangular band in the same style as the plot where I would have the control over the height of that small rectangular band with the legend line in the middle. So for the above example the sin curve legend should look something like below with adjustable height.

2] Also is it possible to have different types of lined shading within the error band like for e.g. the commanly used are the chequered shading, forward line shading, backward line shading etc.

Below I have shown a portion of a plot with chequered shaded error band.

then it should have the corresponding chequered shaded legend

## tiling – Monotile that tiles when you apply a rubber band

My (non-mathematician) friend asked me a physics/tilings question that maybe someone here is interested in dissecting, or can point to the literature if this problem has been studied.

Does there exist a tile such that when you put a bunch of copies of it on a table and push from all sides, they always form a tiling?

My friend illustrated with physical (uniform density) lozenge tiles that they do not have this property, by throwing some on the table, and pushing them together. More specifically this suggests the stronger property that a typical initial configuration will get stuck. The tiles this was demonstrated on had positive friction.

The informal question as stated is a bit ambiguous. I am not going to try to formalize the physics of the problem, but I’ll at least try to specify how the force is applied in a hopefully unambiguous (but somewhat arbitrary) way. You can suggest a better variant in the same spirit if e.g. it’s easier to solve or mine misses the point for a “stupid” reason.

Let’s say a **tile** is a nice enough subset $P subset mathbb{R}^2$, you can pick what that means. E.g. if going for a negative answer, you can choose something like “simply connected convex polygon”. If going for a positive answer, I could imagine something like piecewise smooth being helpful. (For physics considerations it’s a zero friction rigid body, and let’s say of uniform density.)

Let $G = mathbb{R}^2 rtimes S^1$ be the rototranslation group (so no flips), which acts on $mathbb{R}^2$ from the left. A **partial tiling** is a subset of $T subset G$ such that the interiors of $t cdot P$ for distinct $t in T$ are disjoint. We say a partial tiling $T$ **fills** $C subset mathbb{R}^2$ if $T cdot P supset C$.

A **jam** is a finite partial tiling $T subset G$ such that, assuming the tiles have zero friction and behave according to physics, if you stretch a rubber band around the convex hull of $T cdot P = bigcup_{t in T} {t cdot P}$, the tiles will not budge. Intuitively, jams always exist aplenty, just put some tiles on the table, stretch the band around them and let go (if there’s a third dimension available there’s a problem with that strategy, but you see what I mean).

Definition. A tile $P$ is a

rubber band monotileif all $r > 0$, there exists $R > 0$ such that every jam whose convex hull contains the ball of radius $R$ fills a ball of radius $r$?

Observe that any rubber band monotile admits a partial tiling that fills the entire plane. In usual terminology, $P$ tiles the plane under rototranslations, and such $P$ is sometimes called a monotile.

In case this question is non-trivial, here’s some starters:

Is the equilateral (or any) triangle a rubber band monotile? Is the square (or any other rhombus, e.g. the lozenge)? Is the hexagon? Any of the pentagon monotiles?

I’m also interested in higher dimensions of course (my friend may or may not be). In one dimension I was able to solve the problem myself.