$ a + b + c = 2001 $ Y $ a> b> c> 0 $ How many ordered triples are possible?
I tried to replace these equations.
$ c + x = b $
$ b + y = a $
well, the equation would be
$ 3c + 2x + y = 2001 $
but I do not know how to solve this, is there a more general formula of stars and bars?